giúp mk nha hiện giờ mk đg cần gấp

câu a) lấy mẫu số chung cộng với nhau

câu b) lấy 1 để ngoài nhân r 1/2-1/3 rồi tương tự

\(a^2+b^2=13\Leftrightarrow a^2+b^2+2ab-2ab=13\Leftrightarrow\left(a+b\right)^2-2ab=13\)

Mà \(a+b-ab=-1\Leftrightarrow ab=a+b+1\)Thay vào phương trình trêm ta có:

\(\left(a+b\right)^2-2\left(a+b+1\right)=13\)

<=> \(\left(a+b\right)^2-2\left(a+b\right)+1=16\)

<=> \(\left(a+b+1\right)^2=4^2\)

<=> \(a+b+1=\pm4\)=> \(ab=\pm4\)

Ta lại có: \(a^2+b^2=13\Leftrightarrow\left(a-b\right)^2+2ab=13\)

+) Với ab=4

thay vào ta có: \(\left(a-b\right)^2+8=13\Leftrightarrow\left(a-b\right)^2=5\Leftrightarrow\left|a-b\right|=\sqrt{5}\)

=> \(P=\left|a^3-b^3\right|=\left|\left(a-b\right)\left(a^2+b^2+ab\right)\right|=\left|a-b\right|\left|a^2+b^2+ab\right|\)

\(=\sqrt{5}\left(13+4\right)=17\sqrt{5}\)

+) Với ab=-4 . Em làm tương tự nhé!

a)

\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)

\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

b)

\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

a) 28
b) em xem lại đề ha

what your name? I can't speak vietnamese