An lười biếng quá!

Sao Nam chăm chỉ quá vậy?

Tích cực lên, Tâm!

Hoàng đang tỉ mỉ đan len.

chỉ cần trả lòi thui nha ko cần phải ghi chi tiết ra đâu nha !

ai trả lời xong thì kết bạn nha

1. 636

2.18

3.69

4.63

5.1018

6.912

7.425

8.248

9.214

10.7086

11.64

12.7039

904 - 268 = 636

100 - 82 = 18

48 + 21 = 69

25 + 38 = 63

903 + 115 = 1018

675 + 237 = 912

856 : 4 = 214

257 + 168 = 425

992 : 4 = 248

28344 : 4 = 7086

Loại 1:

- If i have much time, i will go out with you

- if i don't do homework, i will go to bed

- if i have free time, i will play game

- If I get up early in the morning, I will go to school on time

Loại 2:

- if i were you, i would buy this gift

- if the weather were good, i would go out

- If i knew that, i would be very surprised

- If I were you, I wouldn't do that

Chọn đáp án: B. Các câu 1 – 2 – 4 – 6 – 8

Chọn C

a: =3^3+4+7=3^14

b: =4^(3+4-2)=4^5

c: =2^(8+2-4)=2^6

d: =5^(7+3-4)=5^6

Câu 1:

\(\dfrac{-5}{6}:\dfrac{3}{13}=\dfrac{-5}{6}.\dfrac{13}{3}=\dfrac{-5.13}{6.3}=\dfrac{-65}{18}\) 

Câu 2:

\(\dfrac{5}{9}:\dfrac{5}{-3}=\dfrac{5}{9}.\dfrac{-3}{5}=\dfrac{5.-3}{9.5}=\dfrac{-15}{45}=\dfrac{-1}{3}\) 

Câu 3:

\(\left(-15\right):\dfrac{3}{2}=\left(-15\right).\dfrac{2}{3}=\dfrac{-15.2}{3}=\dfrac{-30}{3}=-10\) 

Câu 4:

\(\dfrac{3}{4}:\left(-9\right)=\dfrac{3}{4}.\dfrac{-1}{9}=\dfrac{3.-1}{4.9}=\dfrac{-3}{36}=\dfrac{-1}{12}\)

Câu 1

\(-\dfrac{5}{6}:\dfrac{3}{13}=-\dfrac{5}{6}.\dfrac{13}{3}=\dfrac{-5.13}{6.3}=-\dfrac{65}{18}\)

Câu 2

\(2:\dfrac{5}{9}:\dfrac{5}{-3}=2.\dfrac{9}{5}.\dfrac{-3}{5}=\dfrac{2.9.\left(-3\right)}{5.5}=-\dfrac{54}{25}\)

Câu 3

\(4:\dfrac{3}{2}:\left(-9\right)=4.\dfrac{2}{3}.\dfrac{1}{-9}=\dfrac{4.2.1}{-9}=-\dfrac{8}{9}\)

Câu 2.

\(R_{13}=\dfrac{R_1\cdot R_3}{R_1+R_3}=\dfrac{30\cdot60}{30+60}=20\Omega\)

\(R_{tđ}=R_2+R_{13}=45+20=65\Omega\)

\(I_m=\dfrac{U}{R}=\dfrac{130}{65}=2A\)

\(I_{13}=I_m=2A\)

\(U_{13}=U-U_2=U-I_2\cdot R_2=130-2\cdot45=40V\)

\(R_1//R_3\Rightarrow U_1=U_3=U_{13}=40V\)

\(I_3=\dfrac{U_3}{R_3}=\dfrac{40}{60}=\dfrac{2}{3}A\)

Câu 3.

\(R_1//R_2\)

\(\Rightarrow R_{tđ}=\dfrac{R_1\cdot R_2}{R_1+R_2}=\dfrac{10\cdot30}{10+30}=7,5\Omega\)

\(U_1=U_2=U_m=15V\)

\(I_1=\dfrac{U_1}{R_1}=\dfrac{15}{10}=1,5A\)

\(I_2=\dfrac{U_2}{R_2}=\dfrac{15}{30}=0,5A\)

\(I_m=I_1+I_2=1,5+0,5=2A\)

1-C ;

2-A;

3-A;

4-C;

5-B;

6-A