Thuc hien phep tinh:
a/ \(\dfrac{2^4.6^7}{9^3.4^6}\)
b/ \(\dfrac{3^{18}.24^4}{9^4.81^5}\)
DH
Những câu hỏi liên quan
Thuc hien phep tinh;
a. \(\frac{2^4.6^7}{9^3.4^6}\)
b. \(\frac{3^{18}.24^4}{9^4.81^5}\)
Thuc hien phep tinh:
a/ dfrac{5}{15}+ dfrac{14}{15} -dfrac{12}{9}+ dfrac{2}{7}+dfrac{11}{25} d/ (9dfrac{3}{4}:5.2+3.4.2dfrac{7}{34}) :(-1dfrac{9}{16})
e/ dfrac{2^8.9^2}{6^4.8^2}
b/ 4.(-dfrac{1}{2})^3+dfrac{1}{2}
c/ dfrac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}
Đọc tiếp
Thuc hien phep tinh:
a/ \(\dfrac{5}{15}\)+ \(\dfrac{14}{15}\) -\(\dfrac{12}{9}\)+ \(\dfrac{2}{7}\)+\(\dfrac{11}{25}\) d/ (\(9\dfrac{3}{4}\):5.2+3.4.\(2\dfrac{7}{34}\)) :(\(-1\dfrac{9}{16}\))
e/ \(\dfrac{2^8.9^2}{6^4.8^2}\)
b/ 4.(\(-\dfrac{1}{2}\))^3+\(\dfrac{1}{2}\)
c/ \(\dfrac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
a: \(=\left(\dfrac{5}{15}-\dfrac{12}{9}\right)+\left(\dfrac{14}{15}+\dfrac{11}{25}\right)+\dfrac{2}{7}\)
\(=\left(\dfrac{1}{3}-\dfrac{4}{3}\right)+\dfrac{70+33}{75}+\dfrac{2}{7}\)
\(=-1+\dfrac{2}{7}+\dfrac{103}{75}=\dfrac{-5}{7}+\dfrac{103}{75}=\dfrac{346}{525}\)
b: \(4\cdot\left(-\dfrac{1}{2}\right)^3+\dfrac{1}{2}\)
\(=4\cdot\dfrac{-1}{8}+\dfrac{1}{2}=\dfrac{-1}{2}+\dfrac{1}{2}=0\)
c: \(\dfrac{10^3+5\cdot10^2+5^3}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot8+5\cdot5^2\cdot2^2+5^3}{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^3}\)
\(=\dfrac{5^3\left(8+4+1\right)}{3^3\left(8+4+1\right)}=\dfrac{125}{27}\)
e: \(\dfrac{2^8\cdot9^2}{6^4\cdot8^2}=\dfrac{2^8\cdot3^4}{3^4\cdot2^4\cdot2^6}=\dfrac{1}{4}\)
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thuc hien phep tinh
( 5*4^15*9-4*3^20*8^9) /( 5*2^9*6^19-7*2^29*27^6)
Tách hai dấu ngoặc thành hai vế A và B
Ta có :
A=5.415.99-4.320.89=5.230.318-22.227.320
=229.318(2.5-32)=229.318
B=5.29.619-7.229.276=5.29.219.319-7.229.318
=228.318(5.3-7.2)=228.318
=>A:B=229.318:228:318=2
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Thuc hien cac phep tinh sau ;a] [5/6 + 6/9 ] * 3/11
b] [ 7/6 - 1/4 ] \ 3/4
Thuc hien phep tinh;
a/ 1dfrac{4}{23}+dfrac{5}{21}-dfrac{4}{23}+0,5+dfrac{16}{21}
b/ left(dfrac{1}{25}+dfrac{1}{5}+1right):left(dfrac{1}{25}-dfrac{1}{5}-1right)
c/ dfrac{dfrac{1}{9}-dfrac{1}{7}-dfrac{1}{11}}{dfrac{4}{9}-dfrac{4}{7}-dfrac{4}{11}}+ dfrac{0,6-dfrac{3}{25}-dfrac{3}{125}-dfrac{3}{625}}{dfrac{4}{5}-0,16-dfrac{4}{125}-dfrac{4}{625}}
d/ dfrac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-dfrac{5^{10}.7^3-25^5.49^2}{left(125.7right)^3+5^9.14^3}
Đọc tiếp
Thuc hien phep tinh;
a/ \(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
b/ \(\left(\dfrac{1}{25}+\dfrac{1}{5}+1\right):\left(\dfrac{1}{25}-\dfrac{1}{5}-1\right)\)
c/ \(\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}\)+ \(\dfrac{0,6-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-0,16-\dfrac{4}{125}-\dfrac{4}{625}}\)
d/ \(\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
a: \(=\left(1+\dfrac{4}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}\)
\(=1+1+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\)
b: \(=\left(\dfrac{1}{25}+\dfrac{5}{25}+\dfrac{25}{25}\right):\left(\dfrac{1}{25}-\dfrac{5}{25}-\dfrac{25}{25}\right)\)
\(=\dfrac{31}{25}:\dfrac{-29}{25}=\dfrac{-31}{29}\)
c: \(=\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}+\dfrac{\dfrac{3}{5}-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-\dfrac{4}{25}-\dfrac{4}{125}-\dfrac{4}{625}}\)
=1/4+3/4
=1
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1) thuc hien phep tinh sau:
a)B=\(\left(\dfrac{5}{7}.0,6:3\dfrac{1}{2}\right)\) .(40%-1,4).(-2)^3
B = ( \(\dfrac{5}{7}.0,6:3\dfrac{1}{2}\)) . ( 40% - 1,4) . \(\left(-2\right)^3\)
= (\(\dfrac{5}{7}.\dfrac{3}{5}\): \(\dfrac{7}{2}\)) . ( \(\dfrac{2}{5}-\dfrac{7}{5}\)) . (-8)
= (\(\dfrac{15}{35}:\dfrac{7}{2}\)) . \(\dfrac{-5}{5}\) . ( -8)
= (\(\dfrac{3}{7}.\dfrac{2}{7}\)) . (-1) . (-8)
= \(\dfrac{6}{49}\) . (-1) . (-8)
= \(\dfrac{-6}{49}\) . (-8)
= \(\dfrac{48}{49}\)
Vậy: B =\(\dfrac{48}{49}\)
Nhớ tick nha
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B=(\(\dfrac{3}{7}.\dfrac{2}{7}\)).(\(\dfrac{4}{10}-\dfrac{14}{10}\)).(-8)
B=\(\dfrac{3}{7}.\left(-1\right)\left(-8\right)\)
B=\(\dfrac{24}{7}\)
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thuc hien phep tinh:
a) \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x}\)
Sửa đề: \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x^2}\)
\(=\dfrac{4x-8+2x+4-5x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x-2}\)
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a,thuc hien phep tinh: 5*(2^2*3^2)^9*(2^2)^6-2*(2^2*3)^14*3^4/5*2^28*3^18-7*2^29*3^18
b,tim cac so nguyen n sao cho: n^2+5*n+9 la boi cua n+3
c,tim x,y nguyen sao cho: xy+2*x+y+11=0
thuc hien phep tinh:
a) \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x^2}\)
\(=\dfrac{4x-8+2x+4-5x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x-2}\)
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