a, \(\dfrac{1}{6}+\dfrac{1}{3}=\dfrac{1}{6}+\dfrac{2}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)

b, \(\dfrac{1}{4}+\dfrac{1}{8}=\dfrac{2}{8}+\dfrac{1}{8}=\dfrac{3}{8}\)

c, \(\dfrac{-5}{12}+\dfrac{2}{-3}=\dfrac{-5}{12}+\dfrac{-8}{12}=\dfrac{-13}{12}\)

a, 1/6 + 1/3

= 1/6 + 2/6

= 3/6 

= 1/2

b, 1/4 + 1/8

= 2/8 + 1/8

= 3/8

c, -5/12 + 2/-3

= -5/12 - 2/3

= -5/12 - 8/12

= -13/12

\(a,\dfrac{1}{6}+\dfrac{1}{3}=\dfrac{1}{6}+\dfrac{2}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)

\(b,\dfrac{1}{4}+\dfrac{1}{8}=\dfrac{2}{8}+\dfrac{1}{8}=\dfrac{3}{8}\)

\(c,\dfrac{-5}{12}+\dfrac{2}{-3}=\dfrac{-5}{12}+\dfrac{-2}{3}=\dfrac{-5}{12}+\dfrac{-8}{12}=\dfrac{-13}{12}\)

a: 2/9-4/9=-2/9

b: 5/7-4/14=5/7-2/7=3/7

c: -2-5/8=-16/8-5/8=-21/8

d: =6/13+14/39=18/39+14/39=32/39

e: =4/5+4/18=72/90+20/90=92/90=46/45

f: =5/30-12/30=-7/30

g: =-63/63=-1

h: =4/13x26=4x2=8

a: 2/9-4/9=-2/9

b: 5/7 - 4/14 = 5/7 - 2/7 = 3/7

c: -2 - 5/8 = - 16/8 - 5/8 = - 21/8

d: = 6/13 + 14/39 = 18/39 + 14/39 = 32/39

e: = 4/5 + 4/18 = 72/90 + 20/90 = 92/90 = 46/45

f: = 5/30 - 12/30 = -7/30

g: = - 63/63 = -1

h: = 4/13 . 26 =4 . 2 = 8

a: \(=-\dfrac{7}{20}\)

b: \(=\dfrac{9}{4}\)

c: \(=-\dfrac{17}{25}\)

a) Gọi d là ƯCLN(n + 1; n + 2)

\(\Rightarrow n+1⋮d\)

\(n+2⋮d\)

\(\Rightarrow\left[\left(n+2\right)-\left(n+1\right)\right]⋮d\)

\(\Rightarrow\left(n+2-n-1\right)⋮d\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

Vậy \(\dfrac{n+1}{n+2}\) là phân số tối giản

b) Gọi d là ƯCLN(n + 1; 3n + 4)

\(\Rightarrow n+1⋮d\) và \(3n+4⋮d\)

Do \(n+1⋮d\Rightarrow3n+3⋮d\)

\(\Rightarrow\left[\left(3n+4\right)-\left(3n+3\right)\right]⋮d\)

\(\Rightarrow\left(3n+4-3n-3\right)⋮d\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

Vậy \(\dfrac{n+1}{3n+4}\) là phân số tối giản

c) Gọi d là ƯCLN(3n + 2; 5n + 3)

\(\Rightarrow3n+2⋮d\) và \(5n+3⋮d\)

Do \(3n+2⋮d\)

\(\Rightarrow5\left(3n+2\right)⋮d\)

\(\Rightarrow15n+10⋮d\)   (1)

Do \(5n+3⋮d\)

\(\Rightarrow3\left(5n+3\right)⋮d\)

\(\Rightarrow15n+9⋮d\)   (2)

Từ (1) và (2) \(\Rightarrow\left[\left(15n+10\right)-\left(15n+9\right)\right]⋮d\)

\(\Rightarrow\left(15n+10-15n-9\right)⋮d\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

Vậy \(\dfrac{3n+2}{5n+3}\) là phân số tối giản

d) Gọi d là ƯCLN(12n + 1; 30n + 2)

\(\Rightarrow12n+1⋮d\) và \(30n+2⋮d\)

Do \(12n+1⋮d\)

\(\Rightarrow5\left(12n+1\right)⋮d\)

\(\Rightarrow60n+5⋮d\)   (3)

Do \(30n+2⋮d\)

\(\Rightarrow2\left(30n+2\right)⋮d\)

\(\Rightarrow60n+4⋮2\)   (4)

Từ (3 và (4) \(\Rightarrow\left[\left(60n+5\right)-\left(60n+4\right)\right]⋮d\)

\(\Rightarrow\left(60n+5-60n-4\right)⋮d\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

Vậy \(\dfrac{12n+1}{30n+2}\) là phân số tối giản

a: Gọi d=ƯCLN(n+1;n+2)

=>n+2-n-1 chia hết cho d

=>1 chia hết cho d

=>d=1

=>PSTG

b: Gọi d=ƯCLN(3n+4;n+1)

=>3n+4-3n-3 chia hết cho d

=>1 chia hết cho d

=>d=1

=>PSTG

c: Gọi d=ƯCLN(3n+2;5n+3)

=>15n+10-15n-9 chia hết cho d

=>1 chia hết cho d

=>d=1

=>PSTG

d: Gọi d=ƯCLN(12n+1;30n+2)

=>60n+5-60n-4 chia hết cho d

=>1 chia hết cho d

=>d=1

=>PSTG

D nhé

C

C

Câu 1 : c

Câu 2 : c

C 

C

b

B.34.06

Đáp án là : b) 43,06

a)  1 , 32   =   33 25

b)  - 3 , 5 =   - 7 2

c)  0 , 84   =   21 25

d)  - 2 , 38   =   119 50

a) 1,32 = 33 25                              

b) -3,5= - 7 2

c) 0,84 = 21 25                                      

d) -2,38 =  119 50