\(A=\dfrac{5}{9.13}-\dfrac{7}{9.25}-\dfrac{13}{19.25}-\dfrac{31}{19.69}\)
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Những câu hỏi liên quan
F=(\(\dfrac{105}{13.20}\)+\(\dfrac{105}{20.27}+...+\dfrac{105}{62.69}\)):(\(\dfrac{5}{9.13}+\dfrac{7}{9.25}+\dfrac{13}{19.25}+\dfrac{31}{19.69}\))
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Tính :
\(\left(\dfrac{112}{13.20}+\dfrac{112}{20.27}+\dfrac{112}{27.34}+...+\dfrac{112}{62.69}\right):\left(-\dfrac{5}{9.13}-\dfrac{7}{9.25}-\dfrac{13}{19.25}-\dfrac{31}{19.69}\right)\)
E=5/9.13+7/9.25+13/19.25+31/19.69
A=112/13.20 + 112/20.27 +... +112/62.69):(-5/9.13 - -7/9.25 - 13/19.25 - 31/19.69)
Tính
E= 5/9.13 + 7/9.25 + 13/19.25 + 31/19.69
Tính hợp lí : (112/13.20+112/20.27+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)
\(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)
Tính hợp lí : (112/13.20+112/20.27+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)
tính :
C=(112/13.20+112/20.27+112/27.34+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)