\(a,x-36:18=12-15\\ \Rightarrow x-2=-3\\ \Rightarrow x=-1\\ b,92-\left(17+x\right)=72\\ \Rightarrow17+x=20\\ \Rightarrow x=3\\ c,720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=18\\ \Rightarrow x=9\\ d,\left(x+2\right)^3-23=41\\ \Rightarrow\left(x+2\right)^3=64\\ \Rightarrow\left(x+2\right)^3=4^3\\ \Rightarrow x+2=4\\ \Rightarrow x=2\)

b: =>x+17=20

hay x=3

d: =>x+2=4

hay x=2

A = 1
B = 3
C = 9
D = 2

a. 128 - 3 x (X + 2) = 23

             3 x (X + 2) = 128 - 23

                   X + 2    = 105 : 3

                    X         = 35 - 2

                    X         = 33

b. (12 x X - 64) x 8 = 4,64

    12 x X - 64         = 4,64 : 8

    12 x X                 = 0,58 + 64

        X                    = 64,58 : 12

         X                   = \(\frac{3229}{600}\)

c. [(4 x X + 28) x 3 + 55] : 5 = 35

    [(4 x X + 28) x 3 + 55]      = 35 x 5

       (4 x X + 28) x 3             = 175 - 55

        4 x X + 28                     = 120 : 3

         4 x  X                           = 40 - 28

          X                                 = 12 : 4

          X                                 = 3

d. 720 : [41 - (2 x X - 5)] = 8 x 5

              41 - (2 x X - 5)  = 720 : (8 x 5)

                    2 x X - 5      = 41 - 18

                   2 x X            = 23 + 5 

                       X              = 28 : 2

                       X              = 14

x nhỏ : dấu nhân

X lớn : X 

a) 58.57+58.150-58.125   

=58.(57+150-125)

=58.    82

=    4756        

b)3².5-2².7+83.2019⁰

=9.5-4.7+83

=45-28+83

=100

c)2019+(-247)+(-53)-2019 

 =(2019-2019)+[ (-247)+(-53)]

0+(-300)

= -300             

d)13.70-50 [(19-3²):2+2³]

=13.70-50[10:2+8]

=13.70-50.13

=13.(70-50)

=13.20

=260

2.

a)x-36:18=12-5   

    x-36:18=6

    x-36=6.18   

     x-36=108

      x=108+36

      x=    144                    

b)92-(17+x)=72

17+x=92-72

17+x=20

x=20-17

x=3

c)720:[41-(2x+5)]=40     

41-(2x+5)=720:40

41-(2x+5)=  18

2x+5=41-18

2x+5=23

2x=23-5

2x=18

x=18:2

x=9                 

d) (x+2)³ -23=41

 (x+2)³ =41+23

 (x+2)³ =64

=> (x+2)³ =4³

=>x+2=4

=>x=4-2

=>x=2

b. 1500(x-7)=0

x-7=0

x=7

c. (2x-4)(48-12x)=0

2x-4=0 hoặc 48-12x=0

x=2 hoặc x=4

d. (x+12)(x-1)=0

x+12=0 hoặc x-1=0

x=-12 hoặc x=1

bài 2 :

a . 128-3(x+4)=23

3(x+4)=105

x+4=35

x=31

b. [(14X+26).3+55]:5=35

(14x+26).3+55=175

(14x+26).3=120

14x+26=40

14x=14

x=1

d. 720:[41-(2X-5)]=23.5

41-(2x-5)=720:(23.5)

41-(2x-5)=144/23

2x-5=799/23

2x=914/23

x=457/23

b, 1500.(x – 7) = 0

<=>1500x-10500=0

<=>1500x=10500

<=>x=7

Vậy x=7

c,(2.x – 4).(48 – 12.x) = 0

\(\Leftrightarrow\)\(\left\{{}\begin{matrix}2x-4=0\\48-12x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\12x=48\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)

Vậy x=2 hoặc x=4

d, (x + 12).(x – 1) =0

\(\Leftrightarrow\left\{{}\begin{matrix}x+12=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-12\\x=1\end{matrix}\right.\)

Vậy x=-12 hoặc x=1

Bài 2:

a) 128- 3(x+ 4) = 23

\(\Leftrightarrow\)128-(3x+12)=23

\(\Leftrightarrow\)128-3x-12=23

\(\Leftrightarrow\)116-3x=23

\(\Leftrightarrow\)3x=116-23

\(\Leftrightarrow\)3x=93

\(\Leftrightarrow\)x=31

Vậy x=31

b) [(14x+ 26). 3+ 55]: 5= 35

\(\Leftrightarrow\)(14x+ 26). 3+ 55=175

\(\Leftrightarrow\)42x+78+55=175

\(\Leftrightarrow\)42x+133=175

\(\Leftrightarrow\)42x=175-133

\(\Leftrightarrow\)42x=42

\(\Leftrightarrow\)x=1

Vậy x=1

d, 720: [41- (2x- 5)]= 23. 5

\(\Leftrightarrow\)720: 41- (2x- 5)=115

\(\Leftrightarrow\)41-(2x- 5)=720:115

\(\Leftrightarrow\)41-(2x- 5)=\(\dfrac{144}{23}\)

\(\Leftrightarrow\)2x-5=\(\dfrac{799}{23}\)

\(\Leftrightarrow\)2x=\(\dfrac{914}{23}\)

\(\Leftrightarrow\)x=\(\dfrac{457}{23}\)

Vậy x=\(\dfrac{457}{23}\)

a, 128 – 3(x+4) = 23

b,  12 x - 4 3 . 8 3 = 4 . 8 4

c, [(4x+28).3+55]:5 = 35

d, 720:[41 – (2x – 5)] =  2 3 . 5

a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)

=>\(\left[2\left(10-x\right)+51\right]:3=5\)

=>\(\left[2\left(10-x\right)+51\right]=15\)

=>\(2\left(10-x\right)=15-51=-36\)

=>10-x=-36/2=-18

=>\(x=10-\left(-18\right)=10+18=28\)

b: \(\left(x-12\right)-15=20-\left(17+x\right)\)

=>\(x-12-15=20-17-x\)

=>\(x-27=3-x\)

=>\(2x=30\)

=>\(x=\dfrac{30}{2}=15\)

c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

=>\(720-\left[41-2x+5\right]=8\cdot5=40\)

=>\(\left[41-2x+5\right]=720-40=680\)

=>-2x+46=680

=>-2x=680-46=634

=>\(x=\dfrac{634}{-2}=-317\)

\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)

c) \(\left(12x-4^3\right).8^3=4.8^4\)

\(12x-64=4.8^4:8^3\)

\(12x-64=32\)

\(12x=32+64\)

\(12x=96\)

\(x=\dfrac{96}{12}\)

\(x=8\)

d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)

\(720:\left(41-2x+5\right):5=35\)

\(720:\left(46-2x\right)=35.5\)

\(720:\left(46-2x\right)=175\)

\(46-2x=720:175\)

\(46-2x=\dfrac{144}{35}\)

\(2x=46-\dfrac{144}{35}\)

\(2x=\dfrac{1466}{35}\)

\(x=\dfrac{1466}{35}:2\)

\(x=\dfrac{733}{35}\)

lm nốt hộ mik 2 ý cuối vs ạ

128 - 3(x + 4) = 23

=> 3(x + 4) = 128 - 23

=> 3(x + 4) = 105

=> x + 4 = 105 : 3

=> x + 4 = 35

=> x = 35 - 4

=> x = 31

Vậy x = 31

[(4x + 28) . 3 + 55] : 5 = 35

=> (4x + 28) . 3 + 55 = 35 . 5

=> (4x + 28) . 3 + 55 = 175

=> (4x + 28) . 3 = 175 - 55

=> (4x + 28) . 3 = 120

=> 4x + 28 = 120 : 3

=> 4x + 28 = 40

=> 4x = 40 - 28

=> 4x = 12

=> x = 12 : 4

=> x = 3

Vậy x = 3

1. 128 - 3.(x+4) = 23

             3.(x+4) = 5

                 x+4  = 5 : 3

                 x+4  = 5/3

                 x      = -7/3

a,  2 3 x + 5 2 x = 2 5 2 + 2 3 - 33

8x+25x = 33

33x = 33

x = 1

b,  260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2

260:(x+4) = 5.13–3.13

x+4 = 260:26

x+4 = 10

x = 6

c,  720 : [ 41 - 2 x - 5 ] = 2 3 . 5

41–(2x–5) = 720:40

2x–5 = 41–18

2x = 28

x = 14

d,  3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2

7(x–12)+35 = 56

7(x–12) = 21

x–12 = 3

x = 15