\(a,4^8.2^{20}=\left(2^2\right)^8.2^{20}=2^{16}.2^{20}=2^{16+20}=2^{36}\\ b,9^{12}.27^5.81^4=\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4=3^{24}.3^{15}.3^{16}=3^{24+15+16}=3^{55}\\ d,25^{20}.125^4=\left(5^2\right)^{20}.\left(5^3\right)^4=5^{40}.5^{12}=5^{40+12}=5^{52}\\ d,x^7.x^4.x^3=x^{7+4+3}=x^{14}\)

a: 4*8*2^20=2^2*2^3*2^20=2^25

b: 9^12*27^5*81^4=3^24*3^15*3^16=3^55

c: 25^20*125^4=5^40*5^12=5^52

d: =x^(7+4+3)=x^14

5.p.p.5.p.2.q.q = 5².p³.q².2 

\(5.p.p.5.p^2.q.4.q=\left(5.5.4\right).\left(p.p.p^2\right).\left(q.q\right)=100p^4.q^2\)

5.p.p.5.p².q.4.q

= 5².p⁴.2².q²

= 10².p⁴.q²

-4^3.(-5)^2

4^3.4^7 = 4^3+7 = 4^10

ta có :

\(3^3.7^3=\left(3.7\right)^3=21^3\)

3³7³=(3.7)³

\(a,5\cdot p\cdot5\cdot p\cdot2q\cdot4q\)

\(=5^2\cdot p^2\cdot2\cdot q\cdot2^2\cdot q\)

\(=5^2\cdot2^3\cdot p^2\cdot q^2\)

\(b,a\cdot a+b\cdot b+c\cdot c\cdot c+d\cdot d\cdot d\cdot d\)

\(=a^2+b^2+c^3+d^4\)

#Urushi

2.5².5³

2.5².5³

Lê Hoàng Minh trả lời sai rồi.

Mình lỡ bấm nhầm.

Đáp án là 2.5.[5 mũ 3]

2,5².5³