So sánh :
\(\left(0,6\right)^9và\left(-0,9\right)^6\)
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So sánh
\(\left(-32\right)^9và\left(-18\right)^{13}\)
329 = (25)9 = 245 < 252 = (24)13=1613<1813
=> (-32)9 > (-18)13
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so sánh:
\(\left[-\frac{1}{5}\right]^9và\left[-\frac{1}{25}\right]^5\)
Ta thấy:
25^5=(5^2)^5=5^(2*5)=5^10>5^9.
=>1/5^9>1/25^5.
=>-1/5^9<-1/25^5.
=>(-1/5)^9<(-1/25)^5.
Vậy ...
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So sánh
\(\left(\frac{1}{15}\right)^9và\left(\frac{1}{20}\right)^7\)
so sánh 2 phân số:
\(\left[\frac{1}{243}\right]^9và\left[\frac{1}{83}\right]^{13}\)
So sánh hai phân số:
\(\left(\frac{1}{243}\right)^9và\left(\frac{1}{83}\right)^{13}\)
\(\left(\frac{1}{243}\right)^9=\left(\frac{1}{3^4}\right)^9=\frac{1}{3^{4.9}}=\frac{1}{3^{36}}\)
\(\left(\frac{1}{83}\right)^{13}\frac{1}{3^{42}}\Rightarrow\left(\frac{1}{81}\right)^{13}
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so sánh:
\(127^{23}và513^{18}\)
\(\left(\frac{1}{243}\right)^9và\left(\frac{1}{83}\right)^{13}\)
Tính:
\(\left\{\left[\left(6,2:0,31-\dfrac{5}{6}.0,9\right).0,2+0,15\right]:0,2\right\}:\left[\left(2+1\dfrac{4}{11}.0,22:0,1\right).\dfrac{1}{33}\right]\)
b) \(0,4\left(3\right)+0,6\left(2\right).2\dfrac{1}{2}.\left[\left(\dfrac{1}{2}+\dfrac{1}{3}\right):0,5\left(8\right)\right]:\dfrac{50}{53}\)
a: \(=\left\{\left[\left(20-\dfrac{1}{4}\right)\cdot0.2\right]+\dfrac{3}{20}\right\}\cdot5:\left[\left(2+\dfrac{25}{11}\cdot\dfrac{22}{100}\cdot10\right)\cdot\dfrac{1}{33}\right]\)
\(=\left\{\left[\dfrac{79}{20}+\dfrac{3}{20}\right]\right\}\cdot5:\left[\dfrac{356}{55}\cdot\dfrac{1}{33}\right]\)
\(=\dfrac{82}{20}\cdot5:\dfrac{3856}{1815}\simeq104,516\)
b: \(=\dfrac{13}{30}+\dfrac{28}{45}\cdot\dfrac{5}{2}\cdot\left[\dfrac{5}{6}:\dfrac{53}{90}\right]\cdot\dfrac{53}{50}\)
\(=\dfrac{13}{30}+\dfrac{14}{9}\cdot\dfrac{3}{2}=\dfrac{83}{30}\)
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Tính:
a)\(\left\{\left[\left(6,2:0,31-\frac{5}{6}.0,9\right).0,2+0,15\right]:0,2\right\}:\left[\left(2+1\frac{4}{11}:0,1\right).\frac{1}{33}\right]\)
b)\(0,4\left(3\right)+0,6\left(2\right)-2\frac{1}{2}.\left[\left(\frac{1}{2}+\frac{1}{3}:0,5\left(8\right)\right)\right]:\frac{50}{53}\)
c)\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
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So sánh:
a/\(3^{12}\) và \(5^8\) c/\(\left(0,6\right)^9\)và \(\left(-0,9\right)^6\)
b/\(8^{12}\)và \(12^8\) d/\(\left(0,3\right)^{100}\)và \(\left(0,5\right)^{201}\)
a/ 312 và 58
312=(33)4=274 58=(52)4=254
vậy 312 > 58
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