Tim x
\(24\times x-24\times5=480\)
giup minh 2 cau nay nhe ^^
1) 120 + ( (999-9x) : 60 ) x ( day la dau nhan ) 24= 480. Tim x
2) 3( x-9 ) + 15 = 12 + 243 : 32. Tim x
Giup mk nhe>.<!!!
Mk dang GAP!!!!!
1) 120 + ( 999 - 9x) : 6) = 20
999 - 9x : 6 = 140
999- 9x = 840
9x = 999 - 840
x = 17 dư 7
tim x
a) 2.\(3^x\) =162
b) \(\left(7\times x-11\right)^3=2^5\times5^2+200\)
c) \(\left(2\times x-15\right)^5=\left(2\times x-15\right)^3\)
a) 2.3x =162
3x =162:2
3x=81
3x=34
vậy x bằng 4
480/x=24/4
\(24\times5^5_{ }+5^2\times5^3\)
`24 xx 5^5 + 5^2 xx 5^3`
`=24 xx 5^5 + 5^5`
`=5^5 (24 +1)`
`=5^5 . 25`
`=5^5 .5^2`
`=5^7`
=24x3125 +\(5^2+5^3\)
=75000+ \(5^5\)
=75000+3125
=78125
\(24\cdot5^5+5^2\cdot5^3\)
\(=24\cdot5^5+5^5\)
\(=5^5\cdot5^2=5^7\)
120 +[(999-9.x): 60].24=480
120 +[(999-9.x): 60].24=480
=> [(999-9.x): 60].24=480 - 120
=> [(999-9.x): 60].24= 360
=> (999-9.x): 60 = 360 : 24
=> (999-9.x): 60 = 15
=> 999 - 9.x = 15.60
=> 999 - 9x = 900
=> 9x = 999 - 900
=> 9x = 99
=> x = 99 : 9
=> x = 11
Tìm x biết 120+[(999-9x):60].24=480
120+[(999-9x):60].24=480
[(999-9x):60].24 = 480 - 120
[(999-9x):60].24 = 360
[(999-9x):60] = 360 : 24
[(999-9x):60] = 15
(999-9x) = 15 x 60
(999-9x) = 900
9x = 999 - 900
9x = 99
x = 99 : 9
x = 11
120+[(999-9x):60]=480-120
[(999-9x):60].24=360
(999-9x):60=360:24
(999-9x):60=15
(999-9x)=15.60
999-9x=900
990x=900
x=990:900
x=?
120+[(999-9x):60].24=480
[(999-9x):60].24 = 480 - 120
[(999-9x):60].24 = 360
[(999-9x):60] = 360 : 24
[(999-9x):60] = 15
(999-9x) = 15 x 60
(999-9x) = 900
9x = 999 - 900
9x = 99
x = 99 : 9
x = 11
Tìm XX biết: (X \times 5 - 19) + (X \times 3 + 24) = 125.(X×5−19)+(X×3+24)=125. \Trả lời: X =X=
Tìm x thuộc số tự nhiên
1440 : [120-(3.x9) ] =120
120 + [ ( 999-9.x) : 60 ] . 24=480
\(1440:\left[120-\left(3.9x\right)\right]=120\) \(120+\left[\left(999-9x\right):60\right].24=480\)
\(120-\left(3.9x\right)=1440:120\) \(\left[\left(999-9x\right):60\right].24=360\)
\(120-\left(3.9x\right)=12\) \(\left(999-9x\right):60=15\)
\(3.9x=120-12\) \(999-9x=900\)
\(3.9x=108\) \(9x=999-900\)
\(9x=108:3\) \(9x=99\)
\(9x=36\) \(x=99:9\)
\(x=4\) \(x=11\)
tim x,biet: 435 + 24 : x = 500 - 65 + 24 : 3
435+24:x = 500 - 65 + 24:3
435+24:x = 435+24:3
=> 24:x= 24:3 (vì chung số hạng 435)
=> x = 3
Theo đề bài ta thấy:
435+24:x=500-65+24:3
Mà 435=500-65 nên chỉ còn 24:x=24:3
\(\Rightarrow\)X=3