\(2\left(5-x\right)+5=1-3x\)

\(10-2x+5=1-3x\)

\(-2x+3x=1-10-5\)

\(x=-14\)

Ta có: \(2\left(5-x\right)+5=1-3x\Leftrightarrow10-2x+5=1-3x\Leftrightarrow15=1-x\Leftrightarrow x=-14\)

Vậy \(x=-14\)

h ai đây

[x+1]+[x+2]+[x+3]+[x+4]+[x+5]=45

=[x+x+x+x+x]+[1+2+3+4+5]=45

=5x+15=45

5x=30

x=30:5

x=6

Vậy x=6

(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45

(x+x+x+x+x)+1+2+3+4+5=45

5x+15=45

5x=45-15

5x=30

x=30:5

x=6

vậy x=6

Jmgoxpig och ogu o chxjf yvb

8vuob 

bn viết tke bố tôi cx ko hiểu đc

(47 - 52). 3 + 27

= -5. 3 + 27

= -15 + 27

= 12

-4(39 - 19) + 30(-5 - 15)

= -4. 20 + 30. (-20)

= -80 - 600

= -680

36. (-9) + 9. (-64)

= -9(36 + 64)

= -9. 100

= -900

\(\dfrac{15}{17}+\dfrac{32}{17}=\dfrac{15+32}{17}=\dfrac{47}{17}\)

47 - 52). 3 + 27

= -5. 3 + 27

= -15 + 27

= 12

?

(5x+6):(x+3)

=(5x+15-9)/x+3

=5-9/x+3

a)\(x^{15}=x\Rightarrow x\in\left\{0;1\right\}\)                                            d)Là ý b

b)\(\left(2x+1\right)^3=125\\ \left(2x+1\right)^3=5^3\Rightarrow2x+1=5\\ 2x=4\\ x=2\)                       e)\(\left(x-3\right)^2=25\\ \Rightarrow\left(x-3\right)^2=5^2\\ \Rightarrow\hept{\begin{cases}x-3=5\Rightarrow x=8\\x-3=-5\Rightarrow x=-2\end{cases}}\)

c)\(\left(x-5\right)^4=\left(x-5\right)^6\\ \Rightarrow x-5\in\left\{0;1\right\}\Rightarrow x\in\left\{5;6\right\}\)

[(27^4:9^5)+(625^3:125^4)]-2^3

=[(531441:59049)+(244140625:244140625)]-8

=[9+1]-8

=10-8

=2

Nếu dk thì cko mik nhoa

-2x - (x-17) = 34 - (-x+25)

-2x-x+17 = 34+x-25

-3x+17 = x+9

-3x-x = 9-17

-4x = -8

x = -8 : (-4)

x = 2

vậy____

trả lời đi các bạn

-2x-(x-17)=34-(-x+25)

=> -2x-x+17=34+x-25

=> -3x+17=x+9

=> -3x-x=9-17

= -4x=-8 => x=2