(5-x) + 5 = 1-3x
=> 5 - x + 5 = 1 - 3x
=> (5+5) - x = 1 - 3x
=> 10 - x = 1 - 3x
=> -x + 3x = 1 - 10
=> 2x = 9
=> x = \(\frac{9}{2}\)
2 nhân mở ngoặc 5-x đóng ngoặc cộng 5 bằng 1-3x
Ta có: \(\left(5-x\right)+5=1-3x\)
\(\Rightarrow5-x+5=1-3x\)
\(\Rightarrow5+5-1=-3x+x\)
\(\Rightarrow9=\left(-3+1\right)x\)
\(\Rightarrow9=-2x\)
\(\Rightarrow9\div\left(-2\right)=x\)
\(\Rightarrow x=\frac{9}{-2}\)
Vậy \(x=-\frac{9}{2}\)