Question

\(x^2\)+\(y^2\)-4x+6y+13=0 

Tìm x

Answer 1

x²+y²-4x+6y+13=0

(x²-4x+4)+(y²+6y+9)=0

(x-2)²+(y+3)²=0

suy ra x-2=0 hoặc y+3=0

*x-2=0=>x=2      *y+3 =0=> y=-3

vậy x=2,y=-3