Question

(x+2)^2-(x-3)(x+1)=2

Answer 1

\(x^2+4x+4-x^2-x+3x+3-2=0\)

\(6x+5=0\)

\(x=\dfrac{-5}{6}\)

Answer 2

\(\left(x+2\right)^2-\left(x-3\right)\left(x+1\right)=2\)

\(\Leftrightarrow x^2+4x+4-x^2+2x+3=2\)

\(\Leftrightarrow6x=-5\Leftrightarrow x=-\dfrac{5}{6}\)

Answer 3

x = -5/6