Question

Tính

a) \(\frac{3}{5}+\frac{1}{10}_{ }-\frac{6}{5}\)

b)\(1\frac{3}{4}.\frac{2}{7}+1\frac{3}{4}.\frac{5}{7}\)

c)\(\left(\frac{3}{4}\right)^2.\sqrt{16}+\left[\left(-2\right)^3;\left(-8\right)-1^{2019}\right]\)

Answer 1

a) \(\frac{3}{5}+\frac{1}{10}-\frac{6}{5}\)

\(=\left(\frac{3}{5}-\frac{6}{5}\right)+\frac{1}{10}\)

\(=\left(-\frac{3}{5}\right)+\frac{1}{10}\)

\(=-\frac{1}{2}.\)

b) \(1\frac{3}{4}.\frac{2}{7}+1\frac{3}{4}.\frac{5}{7}\)

\(=1\frac{3}{4}.\left(\frac{2}{7}+\frac{5}{7}\right)\)

\(=1\frac{3}{4}.1\)

\(=\frac{7}{4}.1\)

\(=\frac{7}{4}.\)

c) Sao lại có dấu chấm phẩy thế kia?

Chúc bạn học tốt!

Answer 2

a) \(\frac{3}{5}+\frac{1}{10}-\frac{6}{5}=\frac{6+1-12}{10}=\frac{-5}{10}=\frac{-1}{2}\)

b) \(1\frac{3}{4}.\frac{2}{7}+1\frac{3}{4}.\frac{5}{7}=1\frac{3}{4}\left(\frac{2}{7}+\frac{5}{7}\right)=1\frac{3}{4}.1=1\frac{3}{4}=\frac{7}{4}\)

c)\(\left(\frac{3}{4}\right)^2.\sqrt{16}+\left[\left(-2\right)^3:\left(-8\right)-1^{2019}\right]=\frac{9}{16}.4+\left[\left(-8\right):\left(-8\right)-1\right]=\frac{9}{16}.4=\frac{9}{4}\)