\(\dfrac{11\cdot3^7\cdot9^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(=\dfrac{11\cdot3^7\cdot3^{14}-3^{30}}{2^2\cdot3^{28}}\)
\(=\dfrac{3^{21}\left(11-3^9\right)}{2^2\cdot3^{28}}\)
\(=\dfrac{11-3^9}{2^2\cdot3^7}\)
Cho E=2^15.0,5^5+3.2^10/2^11.2^3-2^15:2^3 Cho F=2.6^7+6^8/2^5.9^4-2.3^7+3^8 Cho G=4^5.9^4-2.6^9/2^10.3^8+6^8.20
Chứng minh rằng
a) (8^7-2^18) chia hết cho 14
b) (81^7-27^9-9^13) chia hết cho 15
B1 Tính :
a, ( \(\dfrac{-1}{3}\))2 . ( \(\dfrac{-1}{3}\))
b, ( \(\dfrac{1}{7}\))7 . 77 ( 7 mũ 7 nha )
c, 8/4 ( 8 mũ 4 , 4 mũ 4 )
d, 90/15 ( 90 mũ 3 , 15 mũ 3 )
e, 2.3+2.3/10 ( 3 mũ 3, cả 2 số 3 đó ) còn 2 bên phải là mũ 3
3/1^2.2^2 + 5/2^2.3^2 + 1/3^2.4^2+....19/9^2.10^2 < 1
a)\(\frac{45^{10}.5^{10}}{75^{10}}\)
b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
c)\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
d) \(\frac{14^{16}.21^{32}.45^{48}}{10^{16}.15^{32}.7^{96}}\)
Bài khó mà nhìu wa
1)\(2^{17}+2^{14}\)chia hết cho 9
2)\(8^7-2^{18}\)chia hết cho 14
Cứu
chung minh rang
a, \(7^8+7^7-7^6⋮55\)
b ,\(16^5+2^{15}⋮33\)
c, \(81^7-27^9-9^{13}⋮405\)
Chứng minh rằng
a, \(7^6+7^5-7^4\) chia hết cho 55
b, \(81^7-27^9-9^{13}\) chia hết cho 405
c, \(16^5+2^{15}\) chia hết cho 33
15. Tính:
a) \(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
b) \(\frac{\left(\frac{2}{7}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
mình cần lắm ạ, tối nay phải nộp rồi cám ơn các bn trc :''(
