\(C=-7x^2+13x+27\\ =-\left(7x^2-13x-27\right)\\ =-7\left(x^2-\dfrac{13}{7}x-\dfrac{27}{7}\right)\\ =-7\left(x^2-2.x.\dfrac{13}{14}+\dfrac{169}{196}-\dfrac{925}{196}\right)\\ =-7\left(x-\dfrac{13}{14}\right)^2+\dfrac{925}{28}\le\dfrac{925}{28}\)
Dấu "=" xảy ra khi x=13/14
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