\(\left(x+1\right)^4-6\left(x+1\right)^2-\left(x^2-2\right)\left(x^2+2\right)\\ =x^4+4x^3+6x^2+4x+1-6x^2-12x-6-x^4+4\\ =4x^3-8x+5\)
rut gon bieu thuc :
a,\(\left(a+b\right)^3-\left(a-b\right)^3-6a^2b\)
b,\(\left(a+b\right)^3+\left(a-b\right)^3-6ab^2\)
Bài 2.Rút gọn biểu thức
a) \(\left(x^2-1\right)^3-\left(x^4+x^2+1\right)\left(x^2-1\right)\)
b) \(\left(x^4-3x^2+9\right)\left(x^2+3\right)+\left(3+x^2\right)^3\)
c) (\(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2\)
Em cảm ơn ạ <3
Tìm x:
a. \(\left(3x+4\right)\left(3x-4\right)-\left(2x+5\right)^2=\left(x-5\right)^2+\left(2x+1\right)^2-\left(x^2-2x\right)+\left(x-1\right)^2\)
b. \(-5\left(x+3\right)^2+\left(x-1\right)\left(x+1\right)+\left(2x-3\right)^2=\left(5x-2\right)^2-5x\left(5x+3\right)\)
Tìm \(x\):
a,\(\left(x-3\right).\left(x+3\right)-\left(x-2\right)^2=6\)
b,\(\left(2x-1\right)^2-\left(x+2\right)^2-\left(x+2\right).\left(x-2\right)=4\)
Tìm x , biết :
a. \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=15\)
b. \(2x^3-50x=0\)
c.\(5x^2-4\left(x^2-2x+1\right)-5=0\)
d. \(x^3-x=0\)
e. \(27x^3-27x^2+9x-1=1\)
BT1: Viết các biểu thức sau dưới dạng bình phương1 tổng(hiệu):
a, \(x^2+12x+36\)
b, \(x^2-x+\dfrac{1}{4}\)
BT2: Rút gọn biểu thức:
a, \(\left(x^2-1\right)^3-\left(x^4+x^2+1\right)\left(x^2-1\right)\)
b, \(\left(x^4-3x^2+9\right)\left(x^2+3\right)-\left(3+x^2\right)^3\)
c, \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2\)
BT3: Tìm x:
a, \(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)
b, \(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)=28\)
c, \(\left(x^2-1\right)^3-\left(x^4+x^2+1\right)\left(x^2+1\right)=0\)
BT4: Tìm GTNN của:
\(A=x^2-4x+7\)
\(B=2x^2-6x\)
Giúp mình với mình cần gấp!!! Cảm ơn các bạn nhiều nha!!!
Các bạn giúp mình bài toán sau
\(\left(x+2\right)^3\text{-}\left(x+1\right)\left(x^2\text{-}x+1\right)=10\)
\(\left(x\text{-}1\right)^3\text{-}\left(x\text{-}2\right)\left(x^2+x+4\right).3x\left(x+1\right)=0\)
\(\left(x\text{-}3\right)^2\text{-}\left(x\text{-}2\right)\left(x^2+2x+4\right)\text{-}9x\left(x\text{-}1\right)=0\)
1)rút gọn
a) (x+5)(\(x^2\) - 5x + 25) - \(\left(x+3\right)^3\) + (x-2)(\(x^2\) + 2x + 4) - \(\left(x-1\right)^3\)
b)\(\left(x+3y\right)^3+\left(3x+2y\right)\left(9x^2-6xy+4y^2\right)-\left(2y-3x\right)^3\)
c)\(\left(3x+y\right)^3-\left(5x-y\right)\left(25x^2+5xy+y^2\right)+\left(x+2y\right)^3\)
2)tìm x,biết
a)\(\left(x-1\right)^2-\left(x-2\right)\left(x+3\right)+\left(x+2\right)^3=\left(x-3\right)\left(x^2+3x+9\right)+6x\left(x+2\right)\)
Cảm ơn các bạn ^^
Rút gọn
\(A=\left(x+2\right)^2-\left(x-2\right)^2-2.\left(x+1\right).\left(x-1\right)\)
\(B=3.\left(x+3\right)^2-\left(x-2\right)^2-2.\left(x+1\right).\left(x-1\right)\)