Question

\(\left|5x-27\right|^{2017}\)+\(\left(7y+10\right)^{2018}\)=0

Answer 1

Ta có :

\(\left|5x-27\right|^{2017}+\left(7y+10\right)^{2018}=0\)

Ta thấy :

\(\left\{{}\begin{matrix}\left|5x-27\right|^{2017}\ge0\\\left(7y+10\right)^{2018}\ge0\end{matrix}\right.\)

Dấu "=" xảy ra khi :

\(\left\{{}\begin{matrix}\left|5x-27\right|^{2017}=0\\\left(7y+10\right)^{2018}=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left|5x-27\right|=0\\7y+10=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}5x-27=0\\7y=-10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{27}{5}\\y=-\dfrac{10}{7}\end{matrix}\right.\)

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