Al4C3+12H2O--->3CH4+4Al(OH)3
..........................3/4 mol...x mol
Na + H2O ----> NaOH + 1/2H2
x mol...............x mol.....1/2x mol
NaOH + Al(OH)3 --------> NaAlO2 + 2H2O
x mol.....x mol
=====> 3/4x + 1/2x = 3.36/22.4=0,15 mol
-----------> x= 0,12 mol ------> m= 0,12 * 23 = 2,76g =====>A