Chữ hợi hẹp nên khó nhìn, bn cho to ra nhé
PTHH: Na2SO3 + 2HCl ---> 2NaCl + H2O + SO2
Ta có: \(n_{SO_2}=\dfrac{6,2}{22,4}\approx0,3\left(mol\right)\)
Theo PT: \(n_{HCl}=2.n_{SO_2}=2.0,3=0,6\left(mol\right)\)
Ta có: \(C_{M_{HCl}}=\dfrac{0,6}{V_{dd_{HCl}}}=0,2M\)
=> \(V_{dd_{HCl}}=3\left(lít\right)\)