\(\dfrac{3^{17}.81^{11}}{27^{10}.9^{15}}\)
\(\dfrac{3^{17}.81^{11}}{27^{10}.9^{15}}=\dfrac{3^{17}.\left(3.27\right)^{11}}{27^{10}.\left(3^2\right)^{15}}=\dfrac{3^{17}.3^{11}.27^{11}}{27^{10}.3^{30}}=\dfrac{3^{28}.27^{10}.27}{27^{10}.3^{28}.3^2}=^{ }\dfrac{27}{3^2}=\dfrac{27}{9}=3\)