Question

3^17 nhân 81^11 phần 27^10 nhân 9^15

Answer 1

\(3^{17}.81^{11}:27^{10}.9^{15}\)

=\(3^{17}.\left(3^4\right)^{11}:\left(3^3\right)^{10}.\left(3^2\right)^{15}\)

=\(3^{17}.3^{44}:3^{30}.3^{30}\)

=\(3^{17+44-30+30}\)

=\(3^{61}\)