\(\dfrac{-4}{5}.39\dfrac{1}{3}-\dfrac{-4}{5}.19\dfrac{1}{3}=\dfrac{-4}{5}\left(39\dfrac{1}{3}-19\dfrac{1}{3}\right)=\dfrac{-4}{5}.20=-16\)
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\(-\dfrac{4}{5}.\left(39\dfrac{1}{3}-19\dfrac{1}{3}\right)=-\dfrac{4}{5}.20=\left(-16\right)\)
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