Question

chứng minh 11 + 6√2 = (3 + √2) mũ 2

Answer 1

Ta có:

VT = 11 + 6√2

= 9 + 2.3.√2 + 2

= 3² + 2.3.√2 + (√2)²

= (3 + √2)²

= VP

Vậy 9 + 6√2 = (3 + √2)²

Answer 2

Ta có: \(VT=11+6\sqrt{2}\)

\(=9+6\sqrt{2}+2\)

\(=3^2+2\cdot3\cdot\sqrt{2}+\left(\sqrt{2}\right)^2\)

\(=\left(3+\sqrt{2}\right)^2=VP\left(đpcm\right)\)