Nửa chu vi: \(45:2=\dfrac{45}{2}\)
Gọi 3 cạnh lần lượt là a,b,c(a,b,c>0)
Áp dụng t/c dtsbn:
\(\dfrac{a}{2}=\dfrac{b}{3}=\dfrac{c}{4}=\dfrac{a+b+c}{2+3+4}=\dfrac{\dfrac{45}{2}}{9}=\dfrac{5}{2}\)
\(\Rightarrow\left\{{}\begin{matrix}a=\dfrac{5}{2}.2=5\\b=\dfrac{5}{2}.3=\dfrac{15}{2}\\c=\dfrac{5}{2}.4=10\end{matrix}\right.\)
Áp dụng t/c dtsbn:
\(\dfrac{AB}{2}=\dfrac{BC}{3}=\dfrac{CA}{4}=\dfrac{AB+BC+CA}{2+3+4}=\dfrac{45}{9}=5\\ \Rightarrow\left\{{}\begin{matrix}AB=10\\BC=15\\CA=20\end{matrix}\right.\)