Question

6x^4+5x^3-38x^2+5x+6 phan tich da thuc thanh nt

Answer 1

\(=6x^3\left(x-2\right)+17x^2\left(x-2\right)-4x\left(x-2\right)-3\left(x-2\right)\)

\(=\left(6x^3+17x^2-4x-3\right)\left(x-2\right)\)

\(=\left[6x^2\left(x+3\right)-x\left(x+3\right)-\left(x+3\right)\right]\left(x-2\right)\)

\(=\left(x-2\right)\left(x+3\right)\left(6x^2-x-1\right)\)

\(=\left(x-2\right)\left(x+3\right)\left[2x\left(3x+1\right)-\left(3x+1\right)\right]\)

\(=\left(x-2\right)\left(x+3\right)\left(2x-1\right)\left(3x+1\right)\)