| x-4 | +| x +4 | = x + 8
do | x - 4 | + | x +4 | \(\ge0\Rightarrow x+8\ge0\Rightarrow x\ge0\)
\(\Rightarrow x-4+x+4=x+8\)
\(\Rightarrow x+x=x+8\)
\(\Rightarrow x=8\)
| x-4 | +| x +4 | = x + 8
do | x - 4 | + | x +4 | \(\ge0\Rightarrow x+8\ge0\Rightarrow x\ge0\)
\(\Rightarrow x-4+x+4=x+8\)
\(\Rightarrow x+x=x+8\)
\(\Rightarrow x=8\)
tim x biet |x+2| +|x+3| = 4(x-1) - |x-1|
|x+2|+|3*x-1|+|2*+1|=4
Tim x
tim x bt :
\(\left|x\left(x-4\right)\right|\) =x
Câu 1: Tinh
\(A=\left(\dfrac{3}{5}\right)^2.5^2-\left(2\dfrac{1}{4}\right)^3:\left(\dfrac{3}{4}\right)^3+\dfrac{1}{2}\)
\(B=\left[\dfrac{4}{11}.\left(\dfrac{1}{25}\right)^0+\dfrac{7}{22}.2\right]^{2010}-\left(\dfrac{1}{2^2}:\dfrac{8^2}{4^4}\right)^{2009}\)
\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)
\(\dfrac{3}{2}-\dfrac{5}{6}:\left(\dfrac{1}{2}\right)^2+\sqrt{4}\)
Câu 2: Tim x
\(2.x-\dfrac{5}{4}=\dfrac{20}{15}\)
\(\left(x+\dfrac{1}{3}\right)^3=\left(\dfrac{-1}{8}\right)\)
Tìm x ; y :
a , / 2x-6 / + / x + 3 / = 8
b , / 2x - 1 / + 2x - 5 / = 4
c , / x + 1 / + / x + 2 / + / x + 3 / + / x + 4 / = 5x - 1
Giúp em với ???
Tìm x , biết :
1, |\(\dfrac{3}{2}\)x + \(\dfrac{1}{2}\)| = | 4x - 1 |
2, | \(\dfrac{5}{4}\)x - \(\dfrac{7}{2}\) | - | \(\dfrac{5}{8}x+\dfrac{3}{5}\) | = 0
3, | \(\dfrac{7}{5}x+\dfrac{2}{3}\) | = | \(\dfrac{4}{3}x-\dfrac{1}{4}\) |
4, | \(\dfrac{7}{8}x+\dfrac{5}{6}\) | - | \(\dfrac{1}{2}x+5\) | = 0
Vẽ 2 đừơng thẳng a va b cắt nhau tai I sao cho cac goc tao thanh co 1 goc con lai
Tìm x,biết
A,x-15=1
B, -x-1/2=3/7
C,2x-9=9
Tim x
/x/=5
/x/o
/x/=10
Thuc hien phet tinh
1/-2×2/3×-3/4×-4/5
Tìm 3/5 cua 15
Tìm 1/4 cua 20
Lam nhanh giup voi
Tìm x biết
a) |x+5| + |x-3|=9
b)|x+1| + |x-2| +|x+3|=6
c) |x-2|+|x+3|+|x-4|=2
d) 2|x+2|+|4-x|=22
e)|x-2|+|x-3|+2x-8|=9
f)3x|x+1|-2x|x+2|=12
g)|x-1|+3|x-3|-2|x-2|
lm giúp mình với mk đag cần gấp!HEPL MEEEE
Tìm x
3/2 - ( x - 2 1/3) = |-3/4 - 1 1/8|