\(\dfrac{3}{2}-\left(x-2\dfrac{1}{3}\right)=\left|\dfrac{-3}{4}-1\dfrac{1}{8}\right|\)
\(\Leftrightarrow\dfrac{3}{2}-\left(x-2\dfrac{1}{3}\right)=\left|\dfrac{-3}{4}-\dfrac{9}{8}\right|\)
\(\Leftrightarrow\dfrac{3}{2}-\left(x-\dfrac{7}{3}\right)=\left|\dfrac{-15}{8}\right|\)
\(\Leftrightarrow\dfrac{3}{2}-\left(x-\dfrac{7}{3}\right)=\dfrac{15}{8}\)
\(\Leftrightarrow x-\dfrac{7}{3}=\dfrac{3}{2}-\dfrac{15}{8}\)
\(\Leftrightarrow x-\dfrac{7}{3}=\dfrac{-3}{8}\)
\(\Leftrightarrow x=\dfrac{-3}{8}+\dfrac{7}{3}=\dfrac{47}{24}\)
Vậy ...
\(\dfrac{3}{2}-\left(x-2\dfrac{1}{3}\right)=\left|\dfrac{-3}{4}-1\dfrac{1}{8}\right|\)
\(\Leftrightarrow\dfrac{3}{2}-\left(x-\dfrac{7}{3}\right)=\left|\dfrac{-15}{8}\right|\)
\(\Leftrightarrow\dfrac{3}{2}-\left(x-\dfrac{7}{3}\right)=\dfrac{15}{8}\)
\(\Leftrightarrow x-\dfrac{7}{3}=\dfrac{-3}{8}\)
\(\Leftrightarrow x=\dfrac{-3}{8}+\dfrac{7}{3}\)
\(\Rightarrow x=\dfrac{47}{24}\)
Vậy \(x=\dfrac{47}{24}\)
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