\(\left(\dfrac{-1}{2}\right)^3+\left(\dfrac{-1}{2}\right)^2+\left(\dfrac{-1}{2}\right)^1+\left(\dfrac{-1}{2}\right)^0\)
= \(\left(\dfrac{-1}{8}\right)+\dfrac{1}{4}+\left(\dfrac{-1}{2}\right)+1\)
= \(\left(\dfrac{-1}{8}\right)+\dfrac{2}{8}+\left(\dfrac{-4}{8}\right)+\dfrac{8}{8}\)
= \(\dfrac{\left(-1\right)+2+\left(-4\right)+8}{8}\)
= \(\dfrac{5}{8}\)
bài 1:
a) (\(-\dfrac{1}{2}\))3 + (\(\dfrac{5}{6}\))0 - (\(-\dfrac{3}{2}\))2-(-1)10
b) 4(\(-\dfrac{1}{3}\))0 - 2(\(-\dfrac{1}{2}\))2+3(\(-\dfrac{1}{2}\))+1
Bài 2:
a)(4x - 3)x=-125
tính:
a,(2\(^{-1}\)+3\(^{-1}\)):(2\(^{-1}\)- 3\(^{-1}\))+(2\(^{-1}\).2\(^0\)):\(2^3\)
b, \(\left(\frac{-1}{3}\right)\)\(^{-1}\)- \(\left(-\frac{6}{7}\right)\)\(^0\)+\(\left(\frac{1}{2}\right)\)\(^2\):2
1) a) (x-\(\dfrac{1}{2}\))^2=0
b) (x-2)^2=1
c)(2x-1)3=-8
d)(x+\(\dfrac{1}{2}\))^2=\(\dfrac{1}{16}\)
mik xl vì hỏi nhìu nha nhưng bài khó lắm á
a) [x-1/2]3=1/27
b)(x+2021).(1/2-x)=0
3-(-6)0/7+(1)2/2:2
Tính:
a) M=810+410/84+411
b)(32)2-(-23)2-(-52)2
c)E=23.3(-1/2)0.(1/2)2.4+/(-2)2:1/2
\(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
C=\(\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{99}}< -\frac{1}{2}\)
D=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)< -\frac{1}{2}\)
(2x+1)x+(x-1/3)2=0