Cho \(\Delta ABC=\Delta DEF\). Biết \(\widehat{A}+\widehat{B}=130^0\), \(\widehat{E}=55^0\). Tính \(\widehat{A}\), \(\widehat{C}\), \(\widehat{D}\), \(\widehat{F}\)?
- \(\widehat{A}=\widehat{D}=65^0\), \(\widehat{C}=\widehat{F}=50^0\).
- \(\widehat{A}=\widehat{D}=50^0\), \(\widehat{C}=\widehat{F}=65^0\).
- \(\widehat{A}=\widehat{D}=75^0\), \(\widehat{C}=\widehat{F}=50^0\).
- \(\widehat{A}=\widehat{D}=50^0\), \(\widehat{C}=\widehat{F}=75^0\).