Giá trị của biểu thức \(A=\dfrac{5}{18}-1,456:\dfrac{3}{25}+4,5.\dfrac{4}{5}\) là
\(\dfrac{-649}{120}.\)\(\dfrac{-749}{120}.\)\(\dfrac{-849}{120}.\)\(\dfrac{-949}{120}.\)Hướng dẫn giải:\(A=\dfrac{5}{18}-1,456:\dfrac{3}{25}+4,5.\dfrac{4}{5}\)
\(A=\dfrac{5}{18}-\dfrac{182}{125}:\dfrac{3}{25}+\dfrac{9}{2}.\dfrac{4}{5}\)
\(A=\dfrac{5}{18}-\dfrac{182}{15}+\dfrac{18}{5}\)
\(A=\dfrac{-949}{120}.\)
