a, 7\(\dfrac{3}{5}\) : \(x\) = 5\(\dfrac{4}{15}\) - 1\(\dfrac{1}{6}\)

     \(\dfrac{38}{5}\) : \(x\) = \(\dfrac{79}{15}\) - \(\dfrac{7}{6}\)

              \(x\) = \(\dfrac{41}{10}\)

             \(x\) = \(\dfrac{38}{5}\) : \(\dfrac{41}{10}\)

              \(x\) = \(\dfrac{76}{41}\)

b, \(x\) \(\times\) 2\(\dfrac{2}{3}\) = 3\(\dfrac{4}{8}\) + 6\(\dfrac{5}{12}\)

    \(x\) \(\times\) \(\dfrac{8}{3}\)  = \(\dfrac{7}{2}\) + \(\dfrac{77}{12}\)

     \(x\) \(\times\) \(\dfrac{8}{3}\) = \(\dfrac{119}{12}\)

     \(x\)          = \(\dfrac{119}{12}\)

     \(x\)          = \(\dfrac{119}{12}\): \(\dfrac{8}{3}\)

     \(x\)           = \(\dfrac{119}{32}\)

\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)

b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)

x-\(\frac{3}{5}\)x = \(\frac{2}{5}\)

=> x.(1-\(\frac{3}{5}\)) =\(\frac{2}{5}\)

=> x. \(\frac{2}{5}\)= \(\frac{2}{5}\)

=> x=1

Vậy x=1

VD: 1/2 là 1 phần 2 đó nha.

a: x/3-1/6=1/5

=>x/3=11/30

hay x=11/90

b: =>1/2x=2

hay x=4

c: =>2/3:x=-7-1/3=-22/3

=>x=-1/11

a: x/3-1/6=1/5

=>x/3=11/30

hay x=11/90

b: =>1/2x=2

hay x=4

c: =>2/3:x=-7-1/3=-22/3

=>x=-1/11

1.

$-7(5-x)-2(x-10)=15$

$-35+7x-2x+20=15$

$5x-15=15$

$5x=30$

$x=30:5=6$

2.

$3(x-4)-(8-x)=12$

$3x-12-8+x=12$

$4x-20=12$

$4x=12+20=32$

$x=32:4=8$

3.

$7(x-9)-5(6-x)=(-6)+11x$

$7x-63-30+5x=11x-6$

$12x-93=11x-6$

$12x-11x=93-6$

$x=87$

nhưng làm gì 

a)x=15+5=20

b)x=(15-17):2=-1

c)=>x-2=+-3

th1x=-3+2=-5

th2x=3+2=5

d)x-3=+-8

th1x=-8+3=-5

th2x=8+3=11

e)x+1=(72-9):3=+-21

th1x=-21-1=-22

th2x=21-1=20

j)lxl=(17-45):43=-28/43

=>x\(\in\Phi\)

x-1=(7+5):3=+-4

th1x=-4+1=-3

th2x=4+1=5

mk làm tắt đó tự suy luận ra mk làm

xong rồi nha 

bạn đã kiểm tra kĩ chưa vậy?mình đọc đề câu B mà loạn não luôn á;-;

mik kiểm tra rùi