Ta có:

\(A=\dfrac{17^{11}-1}{17^{12}-1}< 1\) ( vì tử < mẫu )

\(\Rightarrow A=\dfrac{17^{11}-1}{17^{12}-1}< \dfrac{17^{11}-1+16}{17^{12}-1+16}=\dfrac{17^{11}-17}{17^{12}-17}=\dfrac{17.\left(17^{10}-1\right)}{17.\left(17^{11}-1\right)}=\dfrac{17^{10}-1}{17^{11}-1}=B\)

\(\Rightarrow A< B\)

Có A = 17^11 - 1/17^12 - 1

         = 17^10 . 17 - 1/17^11 . 17 - 1

Có B = 17^10 + 1/17^11 + 1

 Vì 17^11 > 17^10 

Lại có : 1/17^12 < 1/17^11

Mà: 17 > 1/17

=> A > B

A>B                        NHỚ KICK NHA BẠN 

MK cần cả cách trình bày cơ bạn

Ta có:

A=1718+11719+1

⇒17A=1719+1+161719+1

⇒17A=1+161719+1

B=1717+11718+1

⇒17B=1718+1+161718+1

⇒17B=1+161718+1

Vì 161719+1<161718+1⇒17A<17B

⇒A<B

Vậy A<B

k cho mk nha

A>B

tk mk nha

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18 = 171 nhé

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18.  = 171

Bài 1: 

1: \(17A=\dfrac{17^{19}+17}{17^{19}+1}=1+\dfrac{16}{17^{19}+1}\)

\(17B=\dfrac{17^{18}+17}{17^{18}+1}=1+\dfrac{16}{17^{18}+1}\)

mà \(17^{19}+1>17^{18}+1\)

nên 17A>17B

hay A>B

2: \(C=\dfrac{98^{99}+98^{10}+1-98^{10}}{98^{89}+1}=98^{10}+\dfrac{1-98^{10}}{98^{89}+1}\)

\(D=\dfrac{98^{98}+98^{10}+1-98^{10}}{98^{88}+1}=98^{10}+\dfrac{1-98^{10}}{98^{88}+1}\)

mà \(98^{89}+1>98^{88}+1\)

nên C>D

a, \(\sqrt{15}+\sqrt{8}< \sqrt{16}+\sqrt{9}=4+3=7\)

\(\Rightarrow\sqrt{15}+\sqrt{8}< 7\)

b, \(\sqrt{10}+\sqrt{17}+1>\sqrt{9}+\sqrt{16}+1=3+4+1=8\)

\(\sqrt{61}< \sqrt{64}=8\)

\(\Rightarrow\sqrt{10}+\sqrt{17}+1>\sqrt{61}\)

c, \(\sqrt{10}+\sqrt{5}+1>\sqrt{9}+\sqrt{4}+1=3+2+1=6\)

\(\sqrt{35}< \sqrt{36}=6\)

\(\Rightarrow\sqrt{10}+\sqrt{5}+1>\sqrt{35}\)