\(3\cdot2\cdot x-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):\dfrac{11}{3}=\dfrac{7}{20}\)

\(6x-\left(\dfrac{12}{15}+\dfrac{10}{15}\right)\cdot\dfrac{3}{11}=\dfrac{7}{20}\)

\(6x-\dfrac{22}{15}\cdot\dfrac{3}{11}=\dfrac{7}{20}\\ 6x-\dfrac{2}{5}=\dfrac{7}{20}\\ 6x=\dfrac{7}{20}+\dfrac{2}{5}\\ 6x=\dfrac{3}{4}\\ x=\dfrac{1}{8}\)

\(3.2x-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):\dfrac{11}{3}=\dfrac{7}{20}\)

\(\Rightarrow6x-\dfrac{22}{15}:\dfrac{11}{3}=\dfrac{7}{20}\)

\(\Rightarrow6x-\dfrac{2}{5}=\dfrac{7}{20}\)

\(\Rightarrow6x=\dfrac{7}{20}+\dfrac{2}{5}\)

\(\Rightarrow6x=\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{3}{4}:6\)

\(\Rightarrow x=\dfrac{1}{8}\)

\(2^2+\left[10^5:10^4-\left(2+3.2\right)\right]\)

\(=4+\left[10-\left(2+6\right)\right]\)

\(=4+\left(10-8\right)\)

\(=4+2=6\)

1. 2²+[10⁵:10⁴- (2+3.2)]

=4+(10-8)

=4+2

=6

2. x chia hết 2,x chia hết 4 , x <20 

cho thêm điều kiện (x là số tự nhiên)

Ta có:x chia hết cho 2, xchia hét cho 4

=> x thuộc BC(2,4)

ta có: BCNN(2,4)=4

=> x=BC(2,4)=B(4)={0;4;16;64:...}

Mà x<20 => x =o hoặc x=4 hoặc x=16

giup mink ai nhanh tick 3 lan nghia la 1 lan tra loi mot lan noi lam rui mot lan noi cam on

dễ tích mình rồi mình giải cho

1) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)

\(-\frac{2}{3}x+\frac{1}{6}=\frac{2}{3}x-\frac{1}{3}\)

\(-\frac{2}{3}x-\frac{2}{3}x=-\frac{1}{3}-\frac{1}{6}\)

\(-\frac{4}{3}x=-\frac{1}{2}\)

\(x=\left(-\frac{1}{2}\right):\left(-\frac{4}{3}\right)\)

\(x=\frac{3}{8}\)

`=40`

\(=\dfrac{3\cdot2^{x+1}}{2^{x+3}}=\dfrac{3}{2^2}=\dfrac{3}{4}\)

 a) 4x³ + 12 = 120

=> 4x³         = 120 - 12

 => 4x³         = 108

=>   x³           = 108 : 4

=>    x³           = 27

=>        x = 3 

  b) 3 . 2^x - 3 = 45

 =>  3. 2^x       = 45 + 3 

=>    3 . 2^x       = 48

=>         2^x       = 48 :3

=>           2^x       = 16

=>  x = 4

 c) 20 - [ 7 ( x - 3 ) + 4 ] = 2 

=>      7 ( x - 3 ) + 4       = 18

=>        7 ( x - 3 )            = 14

=>            x - 3 = 2

=> x = 5

a, 4x³ +12=120

→ 4x³ = 120-12=108

→x³  =108:4=27

  →x³=3³→x=3

a.4x³ + 12 = 120

<=> 4x³ = 120-12

<=> 4x³=108

<=>x³=108:4

<=>x³=27

<=>x³=3³

=>x=3

vậy x=3

b.3.2^x - 3 =45

<=>3.2^x =45+3

<=>3.2^x=48

<=>2^x=48:3

<=>2^x=16

<=>2^x=2⁴

=>x=4

vậy x=4

c.20 - [ 7 ( x - 3 ) + 4] = 2

<=>7(x-3)+4=20-2

<=>7(x-3)+4=18

<=>7(x-3)=18-4

<=>7(x-3)=14

<=>x-3=14:7

<=>x-3=2

<=>x=2+3

=>x=5

vậy x=5