\(P=\frac{3^{11}\cdot11+3^{11}\cdot21}{3^9\cdot2^5}=\frac{3^{11}\cdot\left(11+21\right)}{3^9\cdot32}=\frac{3^{11}\cdot32}{3^9\cdot32}=3^2=9\)

\(P=\frac{3^{11}.11+3^{11}.21}{3^9.2^5}\)

\(=\frac{3^{11}.\left(11+21\right)}{3^9.32}\)

\(=\frac{3^{11}.32}{3^9.32}\)

\(=3^2=9\)

\(\frac{3}{5.11}+\frac{5}{11.21}+\frac{7}{21.35}+\frac{9}{35.53}=\frac{1}{2}\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{11}-\frac{1}{21}+\frac{1}{21}-\frac{1}{35}+\frac{1}{35}-\frac{1}{53}\right)=\frac{1}{2}\left(\frac{1}{5}-\frac{1}{53}\right)=\frac{1}{10}-\frac{1}{106}

\(A=\dfrac{3^{10}.11+3^{10}+5}{3^9.2^4}\\ A=\dfrac{3^{10}.\left(11+5\right)}{3^9.16}\\ A=\dfrac{3^{10}.16}{3^9.16}\\ A=3\)

\(\dfrac{3^{10}}{3^9}\)

A = \(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\) 

\(A=\dfrac{3^{10}.\left(11+5\right)}{3^9.16}\) 

\(A=\dfrac{3^{10}.16}{3^9.16}\)

 \(A=\dfrac{3^{10}}{3^9}=3\) 

a: Ta có: \(\left(2^2\cdot5\cdot3^3-5^2\cdot2^3+20\right)\cdot3^2-10\)

\(=\left(4\cdot5\cdot27-25\cdot8+20\right)\cdot9-10\)

\(=\left(540-200+20\right)\cdot9-10\)

\(=3240-10=3230\)