5√2-2√5/√5-√2 +6/2-√10
Viết số thích hợp vào chỗ chấm:
2 = … + 1 |
6 = … + 4 |
8 = 5 + … |
10 = … + 2 |
3 = … + 2 |
6 = 3 + … |
8 = … + 4 |
10 = 7 + … |
4 = 3 + … |
7 = 6 + … |
9 = 8 + … |
10 = … + 4 |
4 = … + 2 |
7 = 5 + … |
9 = 7 + … |
10 = 5 + … |
5 = 4 + … |
7 = … + 3 |
9 = 6 + … |
10 = 10 + … |
5 = … + 2 |
8 = 7 + … |
9 = …+ 4 |
10 = 0 + … |
6 = 5 + … |
8 = … + 2 |
10 = 9 + … |
1 = … + 1 |
Lời giải chi tiết:
2 = 1 + 1 |
6 = 2 + 4 |
8 = 5 + 3 |
10 = 8 + 2 |
3 = 1 + 2 |
6 = 3 + 3 |
8 = 4 + 4 |
10 = 7 + 3 |
4 = 3 + 1 |
7 = 6 + 1 |
9 = 8 + 1 |
10 = 6 + 4 |
4 = 2 + 2 |
7 = 5 + 2 |
9 = 7 + 2 |
10 = 5 + 5 |
5 = 4 + 1 |
7 = 4 + 3 |
9 = 6 + 3 |
10 = 10 + 0 |
5 = 3 + 2 |
8 = 7 + 1 |
9 = 5+ 4 |
10 = 0 + 10 |
6 = 5 + 1 |
8 = 6 + 2 |
10 = 9 + 1 |
1 = 0 + 1 |
2=1+1 6=2+4 8=5+3 10=8+2
3=1+2 6=3+3 8=4+4 10=7+3
4=3+1 7=6+1 9=8+1 10=6+4
4=2+2 7=5+2 9=7=2 10=5+5
5=4+1 7=4+3 9=6+3 10=10+0
5=3+2 8=7+1 9=5=4 10=0+10
6=5+1 8=6=2 10=9+1 1=0+1
cop hết mạng kìa
1. Viết thành dạng lũy thừa các tích sau 1) 2-2-2-2-2-2 2) x-x-x-x 3) 7-7-7-7-6-6-6-6 4) 5-5-3-3-4-4 5) 2-3-3-5-5-5-5 6) 1000-10-10-10 Giúp e với ạ
1: 2*2*2*2*2*2=2^6
2: x*x*x*x=x^4
3: =7^4*6^4=42^4
4: =5^2*3^2*4^2=60^2
5: =2*3^2*5^5
6: =10^3*10^3=10^6
>, <, = ?
10 … 5 + 5 | 9 … 2 + 8 | 6 … 6 – 1 |
9 … 5 + 5 | 10 … 7 + 1 | 5 + 2 … 5 + 3 |
2 + 6 … 3 + 2 | 4 + 4 … 5 + 3 | 4 + 5 … 5 + 4 |
Lời giải chi tiết:
10 = 5 + 5 | 9 < 2 + 8 | 6 > 6 – 1 |
9 < 5 + 5 | 10 > 7 + 1 | 5 + 2 < 5 + 3 |
2 + 6 > 3 + 2 | 4 + 4 = 5 + 3 | 4 + 5 = 5 + 4 |
5^2×6^9×10+6^5×2^3×153/5^2×6^8×10-2×6^8×103
Tính nhanh:
\(a,A=\dfrac{\dfrac{5}{4}+\dfrac{5}{5}+\dfrac{5}{7}-\dfrac{5}{11}}{\dfrac{10}{4}+\dfrac{10}{5}+\dfrac{10}{7}-\dfrac{10}{11}}\)\(b,B=\dfrac{2+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\)
giúp mình với
\(a,A=\dfrac{\dfrac{5}{4}+\dfrac{5}{5}+\dfrac{5}{7}-\dfrac{5}{11}}{\dfrac{10}{4}+\dfrac{10}{5}+\dfrac{10}{7}-\dfrac{10}{11}}\\ =\dfrac{5.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}{10.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}\\ =\dfrac{5}{10}\\ =\dfrac{1}{2}\)
Vậy \(A=\dfrac{1}{2}\)
\(b,B=\dfrac{2+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =\dfrac{3.\left(\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}\right)}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =3\)
Vậy \(B=3\)
Bài 3: Tính
1 + 5 =
2 + 3 =
3 + 6 =
4 + 5 =
5 + 1 =
6 + 2 =
7 + 1 =
8 + 1 =
9 + 0 =
10 + 2=
11 + 2 =
1 + 3 =
2 + 6 =
3 + 7 =
4 + 2 =
5 + 2 =
6 + 3 =
7 + 3 =
8 + 2 =
9 + 1 =
10 + 0 =
11 + 3 =
1 + 4 =
2 + 8 =
3 + 2 =
4 + 1 =
5 + 4 =
6 + 4 =
7 + 2 =
8 + 0 =
9 + 2 =
10 + 6 =
11 + 6 =
Bài 4: Tính
6 - 2 =
3 - 1 =
4 - 2 =
5 - 2 =
8 - 5 =
10 - 6 =
4 - 3 =
3 - 3 =
5 - 1 =
2 - 2 =
3 - 1 =
4 - 1 =
2 - 1 =
4 - 3 =
5 - 0 =
9 - 4 =
8 - 6 =
7 - 3 =
8 - 4 =
7 - 6 =
9 - 5 =
7 - 7=
5 - 3 =
5 - 3=
6 - 3 =
7 - 3 =
7 - 6 =
6 - 5 =
9 - 7 =
9 - 3 =
8 - 8 =
8 - 0 =
5 - 3 =
Bài 5: Tính
6 - 2 =
5 + 2 =
9 - 5 =
2 + 0 =
8 + 2 =
4 - 4 =
7 - 3 =
3 + 6 =
7 + 2 =
9 - 5 =
3 + 6 =
1 + 5 =
7 - 6 =
7 + 1 =
3 + 5 =
2 - 1 =
6 + 3 =
5 + 2 =
9 - 4 =
6 + 4 =
4 + 2 =
6 + 1=
7 - 7=
4 + 3 =
7 + 3 =
5 - 2 =
6 - 5 =
8 - 6 =
6 - 4 =
7 - 3 =
10 + 0 =
5 +4 =
8 - 2 =
Viết gọn các tích sau bằng cách dùng lũy thừa :
a) 5 . 5 . 5 . 5 . 5 . 5 . 5
b) 6 . 6 . 6 . 3 . 2
c) 2 . 2 . 2 . 3 . 3
d) 100 . 10 . 10 . 10
a)5.5.5.5.5.5=56
b)6.6.6.3.2=6.6.6.6=64
c)2.2.2.3.3=6.6.2=62.2
d)100.10.10.10=10.10.10.10.10=105
Nguyễn ĐÌnh Dũng sai rồi, ai li ke vậy
a)5.5.5.5.5.5=56
b)6.6.6.3.2=6.6.6.6=64
c)2.2.2.3.3=23.32
d)100.10.10.10=10.10.10.10.10=105
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
Điền dấu >; < hoặc = vào chỗ trống:
a) 9.....7 2....5 0....1 8.....6
7.....9 5.....2 1....0 6.....6
b) 6....4 3.....8 5....1 2.....6
4....3 8.....10 1....0 6.....10
6....3 3.....10 5....0 2.....2
a) 9 > 7 2 < 5 0 < 1 8 > 6
7 < 9 5 > 2 1 > 0 6 = 6
b) 6 > 4 3 < 8 5 > 1 2 < 6
4 > 3 8 < 10 1 > 0 6 < 10
6 > 3 3 < 10 5 > 0 2 = 2
Điền dấu >; < hoặc = vào chỗ trống:
a) 9 > 7 2 < 5 0 < 1 8 > 6
7 < 9 5 > 2 1 > 0 6 = 6
b) 6 > 4 3 < 8 5 > 1 2 < 6
4 > 3 8 < 10 1 > 0 6 < 10
6 > 3 3 < 10 5 > 0 2 = 2
Viết gọn các tích sau bằng cách dùng lũy thừa:
a) 5 . 5 . 5 . 5 . 5 . 5
b) 2 . 2 . 2 . 3 . 3
c) 6 . 6 . 6 . 3 . 2
d) 100 . 10 . 10 . 10
a) 56
b) 23. 32
c) 6.6.6.3.2=6.6.6.6=64
d)100.10.10.10=10.10.10.10.10=105
a) 5 . 5 . 5 . 5 . 5 . 5 . 5 = 56
b) 6 . 6 . 6 . 3 . 2 = 63 . 61
c) 2.2.2.3.3 = 23 . 32
d) 100 . 10 . 10 . 10 = 102 . 103