Tính nhanh
A= \(\frac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
tính nhanh
\(R=\frac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(R=\frac{43^2-11^2}{36,5^2-27,5^2}\)
\(R=\frac{\left(43-11\right)\left(43+11\right)}{\left(36,5+27,5\right)\left(36,5-27,5\right)}\)
\(R=\frac{32.54}{64.9}\)
\(R=3\)
Tính nhanh :
\(R=\frac{43^2-11^2}{\left(36,5^2\right)-\left(27,5^2\right)}\)
\(S=\frac{97^2+83^3-97.83}{180}\)
\(R=\frac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(=\frac{\left(43-11\right)\left(43+11\right)}{\left(36,5-27,5\right)\left(36,5+27,5\right)}\)
\(=\frac{32.54}{9.64}\)
\(=\frac{6}{2}=3\)
Bạn viết sai đề bài rồi
\(S=\frac{97^3+83^3}{180}-97.83\)
\(=\frac{\left(97+83\right)\left(97^2-97.83+83^2\right)}{180}-97.83\)
\(=97^2-97.83+83-97.83\)
\(=\left(97-83\right)^2=14^2=196\)
Trả lời:
\(R=\frac{43^2-11^2}{36,5^2-27,5^2}\)
\(R=\frac{\left(43-11\right).\left(43+11\right)}{\left(36,5-27,5\right).\left(36,5+27,5\right)}\)
\(R=\frac{32.54}{9.64}\)
\(R=3\)
Đề bài sai bạn nhé
\(S=\frac{97^3+83^3}{180}-97.83\)
\(S=\frac{\left(97+83\right).\left(97^2-97.23+83^2\right)}{180}-97.83\)
\(S=97^2-97.83+83^2-97.83\)
\(S=97^2-2.97.83+83^2\)
\(S=\left(97-83\right)^2\)
\(S=14^2\)
\(S=196\)
Tính nhanh
A=\(\dfrac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(A=\dfrac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(=\dfrac{\left(43-11\right)\left(43+11\right)}{\left(36,5-27,5\right)\left(36,5+27,5\right)}\)
\(=\dfrac{32.54}{9.64}=\dfrac{6}{2}=3\)
Tính giá tri biểu thức
a,\(\frac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
b, \(\frac{97^3+83^3-97,83}{180}\)
. Bài 1:Tính nhanh
a) \(35^2 - 25^2\)
b) \(77^2 + 73^2 - 27^2 - 23^2\)
c) \(\frac{43^{2-11^2}}{36,5^2-27,5^2}\)
. Bài 2: CMR \(\forall n\in Z\)
a) \(n^2\left(n+1\right)+2n\left(n+1\right)⋮6\)
b) \(\left(n^3-n\right)⋮6\)
c) \(\left(n^3-19n\right)⋮6\)
1.Tính nhanh:
a. 2022 - 542 + 256.352 b. 621 - 769.373 - 1482
c. \(\frac{42^2-10^2}{\left(36,5\right)^2-\left(27,5\right)^2}\) d. S = \(\frac{93^2+83^2}{180}\) - 97.83
2.Tìm 4 số nguyên liên tiếp biết tích của chúng bằng 120
\(\frac{43^2-11^2}{\left(35,5\right)^2-\left(26,5\right)^2}\)
Tính giá trị biểu thức ?
\(\frac{43^2-11^2}{\left(35,5\right)^2-\left(26,5\right)^2}\)
\(=\frac{\left(43-11\right)\left(43+11\right)}{\left(35,5-26,5\right)\left(25,5+26,5\right)}\)
\(=\frac{32.54}{9.62}=\frac{16.2.9.6}{9.2.31}=\frac{96}{31}\)
1.Tính nhanh:
a. 2022 - 542 + 256.352 b. 621 - 769.373 - 1482
c. \(\frac{42^2-10^2}{\left(36,5\right)^2-\left(27,5\right)^2}\) d. S = \(\frac{93^2+83^2}{180}\) - 97.83
2.Tìm 4 số nguyên liên tiếp biết tích của chúng bằng 120
1
a,
=(202+54).(202-54)+256.352
=37888+256.352
=37888+90112
=128000
b,
=621-769.373-21904
=621-286837-21904
=-308120
c,
42^2-10^2/(36,5)^2-(27,5)^2
=(42-10).(42+10)/(36,5-27,5).(27,5+36,5)
=1664/576=2(8)
1. Tính nhanh :
a) \(202^2-54^2+256.352\)
\(=\left(202-54\right).\left(202+54\right)+256.352\)
\(=148.256+256.352\)
\(=256.\left(148+252\right)=256.400=102400\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(\frac{1,6:\left(1\frac{3}{5}.1,25\right)}{0,64-\frac{1}{25}}-\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right).2\frac{2}{17}}+0,6.0,5:\frac{2}{5}\)