`(3x-4)^3=7+1^2019`

`(3x-4)^3=7+1`

`(3x-4)^3=8`

`(3x-4)^3=2^3`

`=>3x-4=2`

`3x=6`

`x=2`

\(\left(3x-4\right)^3=7+1^{2019}\)

\(\left(3x-4\right)^3=7+1=8=2^3\)

\(=>3x-4=2\)

\(3x=2+4\)

\(3x=6\)

\(x=6:3\)

\(x=2\)

( 3x - 4)³ = 7 + 1 

( 3x - 4)³ = 8

(3x - 4)³ = 2³

3x - 4 = 2

3x = 2 + 4

3x = 6

x = 6 : 3

x = 2

\(a,x+\frac{3}{4}=\frac{1}{4}\)

\(\Rightarrow x=\frac{1}{4}-\frac{3}{4}=-\frac{1}{2}\)

\(b,\frac{2}{3}x-\frac{3}{7}=\frac{1}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{1}{7}+\frac{3}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{4}{7}\)

\(\Rightarrow x=\frac{4}{7}:\frac{2}{3}=\frac{4}{7}\cdot\frac{3}{2}=\frac{6}{7}\)

\(c,1\frac{2}{3}x-50\%x=-1\frac{1}{6}\)

\(\Rightarrow\frac{5}{3}x-\frac{50}{100}x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{50}{100}\right]x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{1}{2}\right]x=-\frac{7}{6}\)

\(\Rightarrow\frac{7}{6}x=-\frac{7}{6}\Leftrightarrow x=-\frac{7}{6}:\frac{7}{6}=-\frac{7}{6}\cdot\frac{6}{7}=-1\)

a,x+\(\frac{3}{4}\)=\(\frac{1}{4}\)

=>x           =\(\frac{1}{4}\)-\(\frac{3}{4}\)

=> x          =\(\frac{-1}{2}\)   

Vậy x=\(\frac{-1}{2}\)

b,\(\frac{2}{3}\)x-\(\frac{3}{7}\)=\(\frac{1}{7}\)

=>\(\frac{2}{3}\)x          =\(\frac{1}{7}\)+\(\frac{3}{7}\)

=>\(\frac{2}{3}\)x           =\(\frac{4}{7}\)      

=>         x            =\(\frac{4}{7}\) :\(\frac{2}{3}\)

=>         x            =\(\frac{4}{7}\).\(\frac{3}{2}\)

=>         x             =\(\frac{6}{7}\)

Vậy x=\(\frac{6}{7}\)

c,\(\frac{12}{3}\)x-50%x   =\(\frac{-11}{6}\)

=>\(\frac{12}{3}\)x-\(\frac{1}{2}\)x=\(\frac{-11}{6}\)

=>x(\(\frac{12}{3}\)-\(\frac{1}{2}\))=\(\frac{-11}{6}\)

=>x(\(\frac{24}{6}\)-\(\frac{3}{6}\))=\(\frac{-11}{6}\)

=>x\(\frac{21}{6}\)              =\(\frac{-11}{6}\)

=>x                           =\(\frac{-11}{6}\):\(\frac{21}{6}\)

=>x                            =\(\frac{-11}{6}\).\(\frac{6}{21}\)

=>x                            =\(\frac{-11}{21}\)

Vậy x=\(\frac{-11}{21}\)

Ý c, mk tưởng 1 2/3 và -1 1/6 là phân số nên mk giải sai ý đó

BÀI GIẢI LẠI :

1\(\frac{2}{3}\)x-50%x=-1\(\frac{1}{6}\)

\(\frac{5}{3}\)x-\(\frac{1}{2}\)x=\(\frac{-7}{6}\)

x(\(\frac{5}{3}\)-\(\frac{1}{2}\))=\(\frac{-7}{6}\)

x\(\frac{7}{6}\)             =\(\frac{-7}{6}\) 

x                       =\(\frac{-7}{6}\):\(\frac{7}{6}\)

x                        =-1

Vậy x=-1

xl vì bài giải trước nha

5) // 3x + 1 / - 5 / = 2

=> / 3x + 1 / -5 = 2 hoặc -2

TH1: / 3x + 1 / - 5 = 2 => / 3x + 1 / = 2 + 5 = 7 => 3x + 1 = 7 hoặc -7

       *1: 3x + 1 = -7 => 3x = -7 - 1 = -8 => x = -8/3

       *2: 3x + 1 = 7 => 3x = 7 - 1 = 6 => x = 6 : 3 = 2

TH2: / 3x + 1 / - 5 = -2 => / 3x + 1/ = -2 + 5 = 3 => 3x + 1 = 3 hoặc -3

        *1: 3x + 1 = 3 => 3x = 3 - 1 = 2 => x = 2/3

        *2: 3x + 1 = -3 => 3x = -3 - 1 = -4 => x = -4/3

Vậy x thuộc { -8/3 ; 2 ; 2/3 ; -4/3 }

7) 3/2 + 4/5 /x - 3/4 / = 7/4

=> 4/5 / x - 3/4 / = 7/4 - 4/5

=> 4/5 / x - 3/4 / = 19/20

=> / x - 3/4 / = 19/20 : 4/5

=> / x - 3/4 / = 19/16

=> / x - 3/4 / = 19/16 hoặc -19/16

tớ ko biết

/ 3x + 1 / - 5 / = 2 => / 3x + 1 / -5 = 2 hoặc -2

TH1: / 3x + 1 / - 5 = 2 => / 3x + 1 / = 2 + 5 = 7 => 3x + 1 = 7 hoặc -7

                  *1: 3x + 1 = -7 => 3x = -7 - 1 = -8 => x = -8/3

                  *2: 3x + 1 = 7 => 3x = 7 - 1 = 6 => x = 6 : 3 = 2

TH2: / 3x + 1 / - 5 = -2 => / 3x + 1/ = -2 + 5 = 3 => 3x + 1 = 3 hoặc -3

                 *1: 3x + 1 = 3 => 3x = 3 - 1 = 2 => x = 2/3

                 *2: 3x + 1 = -3 => 3x = -3 - 1 = -4 => x = -4/3

Vậy x thuộc { -8/3 ; 2 ; 2/3 ; -4/3 }

7) 3/2 + 4/5 /x - 3/4 / = 7/4

=> 4/5 / x - 3/4 / = 7/4 - 4/5

=> 4/5 / x - 3/4 / = 19/20

=> / x - 3/4 / = 19/20 : 4/5

=> / x - 3/4 / = 19/16

=> / x - 3/4 / = 19/16 hoặc -19/16 

Đây là toán lớp 7 mà bạn.

BBạn có trả lời dc ko, ko thì thôi

a) |3x-2|=7

=> 3x-2=7 hoặc 3x-2=-7

=> 3x=9 hoặc 3x=-5

=> x=3 hoặc x=\(-\dfrac{5}{3}\)