a) (x - 2,5)^2 = 9
b)(1 - x)^3 = -8
c)2^4-x = 16
Ta có 2 lệnh sau: x:= 8; If x>5 then x := x +1; Giá trị của x là bao nhiêu?
A. 9
B. 8
C. 5
D. 6
a) x:1/2=1/3+2/9
b) 2/5xX=3-2/3
c)7/8-x=9/16
a: =>x:1/2=5/9
=>x=10/9
b: =>x*2/5=7/3
=>x=7/3:2/5=7/3*5/2=35/6
c: =>x=7/8-9/16=5/16
a) x : 3,1 : 2,5 = 2. b) 32,8 : x : 1,2 =. 8,2.
c) 3*x-1=3/4:15/16 d) 2,5*x +2,5*3,7=2,5*13,7
a, x= 2 x 2,5x 3,1
x=15,5
b, x= 32,8:1,2;8,2
x=10/3
c, x=(3/4x15/16 +1) :3
x=109/192
d, x= 2,x13,7:2,5-3,7
x=10
k cho mình nha!
a, x= 15.5
b x= 10/3
c x= 0.6
d x= 10
Biết (x2+ 3)2 - 5 = \(\dfrac{4}{\left|y-2\right|+1}\). Giá trị của x + y bằng
A. 0
B. 3
C. 1
D. 2
Biết \(\dfrac{a+b}{6}=\dfrac{b+c}{7}=\dfrac{c+a}{8}\) và a + b +c = 14. Giá trị của c bằng
A. 9
B. 8
C. 6
D. 7
Câu 2:
\(\dfrac{a+b}{6}=\dfrac{b+c}{7}=\dfrac{c+a}{8}=\dfrac{2\left(a+b+c\right)}{6+7+8}=\dfrac{28}{21}=\dfrac{4}{3}\\ \Rightarrow\left\{{}\begin{matrix}a+b=\dfrac{4}{3}\cdot6=8\\b+c=\dfrac{4}{3}\cdot7=\dfrac{28}{3}\\c+a=\dfrac{4}{3}\cdot8=\dfrac{32}{3}\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}a=14-\dfrac{28}{3}=\dfrac{14}{3}\\b=14-\dfrac{32}{3}=\dfrac{10}{3}\\c=14-8=6\end{matrix}\right.\)
Vậy chọn C
tìm X
a.3 x X -1=3/4:15/16
b.2,5 x X +2,5 x 3,7 =2,5 x 13,7
mình cần gấp lắm
Tìm x,biết: a)(x-2,5)^4=(x-2,5)^2
b)(3x-1)^10=(3x-1)^20
c)x^8/243=27
d)32^x.16^x=1024
1 . tính :
6/7 + -5/8 : ( -5 ) - 3/16 . ( -2 )2
2 .tính nhanh :
-17/25 . 20/33 + -17/25 . 13/3 + -3/25
3 . tìm x , biết :
a . 3/5 . x - 7/10 . x = -1/2
b . ( x -2,5 ) : 2 1/2 - 2, = 1 1/4
c . ( 2,5 x - 3,6 ) : 1 5/7 = -1
1,
\(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) : (-5) -\(\dfrac{3}{16}\) . \(\left(-2\right)^2\)
= \(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) . \(\dfrac{-1}{5}\) - \(\dfrac{3}{16}\) . 4
= \(\dfrac{6}{7}\) + \(\dfrac{1}{8}\) - \(\dfrac{3}{4}\)
= \(\dfrac{48}{56}\) + \(\dfrac{7}{56}\) - \(\dfrac{42}{56}\)
= \(\dfrac{13}{56}\)
3,
a,\(\dfrac{3}{5}\)x - \(\dfrac{7}{10}\)x = \(\dfrac{-1}{2}\)
x.(\(\dfrac{3}{5}\) - \(\dfrac{7}{10}\)) = \(\dfrac{-1}{2}\)
x.\(\dfrac{-1}{10}\)= \(\dfrac{-1}{2}\)
x =\(\dfrac{-1}{2}\):\(\dfrac{-1}{10}\)
x = 5
c, (2,5x - 3,6) : \(\dfrac{15}{7}\) = -1
( \(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\)) : \(\dfrac{15}{7}\) = -1
\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = -1 . \(\dfrac{15}{7}\)
\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = \(\dfrac{-15}{7}\)
\(\dfrac{5}{2}\)x = \(\dfrac{-15}{7}\) + \(\dfrac{18}{5}\)
\(\dfrac{5}{2}\)x = \(\dfrac{51}{35}\)
x =\(\dfrac{51}{35}\) : \(\dfrac{5}{2}\)
x = \(\dfrac{102}{175}\)
Mình không biết có chỗ nào sai không nữa.
Cho 3 số thực dương x,y,z thỏa mãn \(\dfrac{1}{a}+\dfrac{2}{b}+\dfrac{3}{c}=3\)
Chứng minh \(\dfrac{27a^2}{c\left(c^2+9a^2\right)}+\dfrac{b^2}{a\left(4a^2+b^2\right)}+\dfrac{8c^3}{b\left(9b^2+4c^2\right)}\ge\dfrac{3}{2}\)
Câu 8. (2,5 điểm): Thực hiện các phép tính:
a) $\left(6 x^8 y^2-27 x^8 y\right): 3 x y$.
b) $\left(2 x^2+16 x^8+3 x-4\right)$ : $(2 x-1)$.
c) $\dfrac{x^2}{x^2-4}+\dfrac{1}{x-2}+\dfrac{1}{x+2}$.