a, 32684 + 41325 + 316 +  675

= (32684 +  316) + (41325 + 675)

= 33 000 + 42 000

= 75 000 

b, 25 \(\times\) 18 \(\times\) 4 \(\times\) 2

= (25 \(\times\) 4) \(\times\) (18 \(\times\) 2)

= 100 \(\times\) 36

= 3600

c, 19 \(\times\) 81 + 19 + 18 \(\times\) 19

= 19 \({}\) \(\times\) 81 + 19 \(\times\) 1 + 18 \(\times\) 19

=  19 \(\times\) (81 + 1 + 18) 

=  19 \(\times\)  100 

= 1900 

1666

19999

75000

61000

tick nha

vao google mà tìm nhiều lắm

tick tick cho mik nhá !

a: \(32684+41325+316+675\)

\(=\left(32684+316\right)+\left(41325+675\right)\)

\(=33000+42000=75000\)

b: \(25\cdot18\cdot4\cdot2\)

\(=18\cdot2\cdot\left(25\cdot4\right)\)

\(=36\cdot100=3600\)

c: \(19\cdot81+19+18\cdot19\)

\(=19\left(81+1+18\right)\)

\(=19\cdot100=1900\)

^{A, 32684 + 41325 + 316 + 675}

^{=(32684+316)+(41325+675)}

=33000+42000

=75000

^{B, 25 x 18 x 4 x 2}

^{=(25x4)x(18x2)}

^=100x36

⁼³⁶⁰⁰

^{C, 19 x 81 + 19 + 18 x 19}

=19x(81+18+1)

=19x100

=1900

C bị sai đề bạn ơi

3672:27=136

bằng 136 nha

CẢM ƠN CÁC BẠN

a: 1/201>1/400

1/202>1/400

,,,

1/400=1/400

=>1/201+1/202+...+1/400>1/400+1/400+...+1/400=200/40=1/2

b: 1/5=1/5

1/6<1/5

...

1/17<1/5

=>1/5+...+1/17<1+4/5=9/5<2

`a)25/(x+1)-1 1/6=-1/3-0,5`

`=>25/(x+1)=-1/3-1/2+1+1/6`

`=>25/(x+1)=1/3`

`=>75=x+1`

`=>x=74`

Vậy `x=74`

`b)(2x+25 3/5)^2-9/25=0`

`=>(2x+128/5)=9/25`

`**2x+128/5=3/5`

`=>2x=-125/5=-25`

`=>x=-25/2`

`**2x+128/5=-3/5`

`=>2x=-131/5`

`=>x=-131/10`

Giải:

a) \(\dfrac{25}{x+1}-1\dfrac{1}{6}=\dfrac{-1}{3}-0,5\) 

              \(\dfrac{25}{x+1}=\dfrac{-5}{6}+\dfrac{7}{6}\) 

              \(\dfrac{25}{x+1}=\dfrac{1}{3}\) 

\(\Rightarrow1.\left(x+1\right)=25.3\)  

\(\Rightarrow x+1=75\) 

\(\Rightarrow x=75-1\) 

\(\Rightarrow x=74\) 

b) \(\left(2x+25\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\) 

              \(\left(2x+\dfrac{128}{5}\right)^2=0+\dfrac{9}{25}\) 

             \(\left(2x+\dfrac{128}{5}\right)^2=\dfrac{9}{25}\) 

\(\Rightarrow\left[{}\begin{matrix}\left(2x+\dfrac{128}{5}\right)^2=\left(\dfrac{3}{5}\right)^2\\\left(2x+\dfrac{128}{5}\right)^2=\left(\dfrac{-3}{5}\right)^2\end{matrix}\right.\) 

\(\Rightarrow\left[{}\begin{matrix}2x+\dfrac{128}{5}=\dfrac{3}{5}\\2x+\dfrac{128}{5}=\dfrac{-3}{5}\end{matrix}\right.\) 

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-25}{2}\\x=\dfrac{-131}{10}\end{matrix}\right.\) 

Chúc bạn học tốt!

Nhanh giúp mình với mn

Tìm x hả?

8/x+1/5=2/5+1/3.

8/x+1/5=11/15

x=11/15-1/5

x=8/15