6x = 5¹¹ : 5⁹ + 3¹ - x

<=> 6x = 5² + 3 - x

<=> 6x = 25 + 3 - x

<=> 6x + x = 28

<=> 7x = 28

=> x = 28 : 7

=> x = 4

Vậy x = 4

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Thank ban

Cho minh hỏi 7x ở đâu ra ?!

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a) 5x + 2x = 6^2 - 5^0

7x = 35

x=5

b) 6x + x = 5^11 : 5^9 + 3^1

7x = 28

x=4

c) 5x + 3x = 3^6 : 3^3 *4 +12

8x = 120

x=15

6x + x = 5¹¹ : 5⁹ + 3¹

x . ( 6 + 1 ) = 5² + 3

 x . 7         = 25 + 3

        x . 7  = 28

            x   = 28 : 7

             x  = 4

Vậy x = 4

6x+x=5¹¹:5⁹+3¹

7x=25+3

7x=28

x=28:7

x=4

vậy: x=4

a) \(\left(x+3\right)\left(x+1\right)-x\left(x-5\right)=11\)

\(\Leftrightarrow x^2+x+3x+3-x^2+5x=11\)

\(\Leftrightarrow9x+3=11\)

\(\Leftrightarrow9x=11-3\)

\(\Leftrightarrow9x=8\)

\(\Leftrightarrow x=\dfrac{8}{9}\)

b) \(\left(8x+2\right)\left(1-3x\right)+\left(6x-1\right)\left(4x-10\right)=-50\)

\(\Leftrightarrow\left(8x-24x^2+2-6x\right)+\left(24x^2-60x-4x+10\right)=-50\)

\(\Leftrightarrow2x-24x^2+2+24x^2-64x+10=-50\)

\(\Leftrightarrow-62x+12=-50\)

\(\Leftrightarrow-62x=-50-12\)

\(\Leftrightarrow-62x=-62\)

\(\Leftrightarrow x=\dfrac{-62}{-62}\)

\(\Leftrightarrow x=1\)

a) \(\left(x+3\right)\left(x+1\right)-x\left(x-5\right)=11\)

\(x^2+x+3x+3-x^2+5x=11\)

\(x+8x+3=11\)

\(x+8x=8\)

\(x\left(8+1\right)=8\)

\(x=\dfrac{8}{9}\)

b) \(\left(8x+2\right)\left(1-3x\right)+\left(6x-1\right)\left(4x-10\right)=-50\)

\(8x-24x^2+2-6x+24x^2-60x-4x+10=-50\)

\(-62x+12=-50\)

\(-62x=-62\)

\(x=1\)

\((x-2)^3-(x+5)(x^2-5x+25)+6x^2=11\\\Leftrightarrow (x-2)^3-(x+5)(x^2-5.x+5^2)+6x^2=11 \\\Leftrightarrow x^3-6x^2+12x-8 -(x^3+5^3)+6x^2-11=0 \\\Leftrightarrow 12x-144=0 \\\Leftrightarrow x=12\)

Vậy \(x=12\).

(x−2)3−(x+5)(x2−5x+25)+6x2=11

=>(x−2)3−(x+5)(x2−5.x+52)+6x2=11

=>x3−6x2+12x−8−(x3+53)+6x2−11=0

=>12x−144=0

=>x=12(x−2)3−(x+5)(x2−5x+25)+6x2=11

=>(x−2)3−(x+5)(x2−5.x+52)+6x2=11

=>x3−6x2+12x−8−(x3+53)+6x2−11=0

=>12x−144=0

=>x=12

Vậy x=12x=12.

cho tôi đúng đi

nhấn vào đúng 0 sẽ có câu trả lời

6x+x = 5^2+3

x.(6+1) = 25+3

x.7=28

x=28:7

x=4

Vậy x=4

Nhớ k cho mình nhé!