\(120 + (135 \div x - 13) \times7=134\)
\(11\times(x-6)=4\times x+11\)
NL
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Ba số x,y,z thảo mãn : \(\frac{6}{11}\times x=\frac{9}{2}\times y=\frac{18}{5}\times z\)z và y+z-x = 120 . Khi đó x+y+z=
Tìm a biết $frac{1}{3times7}+frac{1}{7times11}+frac{1}{11times15}+...+frac{1}{atimes(a+4)}frac{50}{609}$13×7+17×11+111×15+...+1a×(a+4)50609.
Đáp số: a
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Tìm a biết $\frac{1}{3\times7}+\frac{1}{7\times11}+\frac{1}{11\times15}+...+\frac{1}{a\times(a+4)}=\frac{50}{609}$.
Đáp số: a =
\(\dfrac{1}{3\times7}+\dfrac{1}{7\times11}+\dfrac{1}{11\times15}+...+\dfrac{1}{a\times\left(a+4\right)}=\dfrac{50}{609}\)
\(\dfrac{1}{4}\times\left(\dfrac{4}{3\times7}+\dfrac{4}{7\times11}+...+\dfrac{4}{a\times\left(a+4\right)}\right)=\dfrac{50}{609}\)
\(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+...+\dfrac{1}{a}-\dfrac{1}{a\times4}=\dfrac{50}{609}\div\dfrac{1}{4}\)
\(\dfrac{1}{3}-\dfrac{1}{a\times4}=\dfrac{200}{609}\)
\(\dfrac{1}{a\times4}=\dfrac{1}{3}-\dfrac{200}{609}\)
\(\dfrac{1}{a\times4}=\dfrac{1}{203}\)
\(a\times4=203\)
\(a=\dfrac{203}{4}\)
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\(\dfrac{1}{3\times7}\)+\(\dfrac{1}{7\times11}\)+\(\dfrac{1}{11\times15}\)+...+\(\dfrac{1}{a\times\left(a+4\right)}\) = \(\dfrac{50}{609}\)
4\(\times\)( \(\dfrac{1}{3\times7}\) +\(\dfrac{1}{7\times11}\)+\(\dfrac{1}{11\times15}\)+...+\(\dfrac{1}{a\times\left(a+4\right)}\)) = \(\dfrac{50}{609}\) \(\times\)4
\(\dfrac{4}{3\times7}\)+ \(\dfrac{4}{7\times11}\)+\(\dfrac{1}{11\times15}\)+...+\(\dfrac{4}{a\times\left(a+4\right)}\) = \(\dfrac{50}{609}\) \(\times\) 4
\(\dfrac{1}{3}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) - \(\dfrac{1}{11}\) + \(\dfrac{1}{11}\)-\(\dfrac{1}{15}\)+...+\(\dfrac{1}{a}\)-\(\dfrac{1}{a+4}\) = \(\dfrac{200}{609}\)
\(\dfrac{1}{3}\) - \(\dfrac{1}{a+4}\) = \(\dfrac{200}{609}\)
\(\dfrac{1}{a+4}\) = \(\dfrac{1}{3}\) - \(\dfrac{200}{609}\)
\(\dfrac{1}{a+4}\) = \(\dfrac{1}{203}\)
a + 4 = 203
\(a\) = 203 - 4
\(a\) = 199
Đáp số: \(a\) = 199
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a) \(5\frac{8}{17}\div x+\frac{-1}{17}\div x+3\frac{1}{17}\div17\frac{1}{3}=\frac{4}{17}\)
b)\(\frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10}+...+\frac{1}{x\times\left(x+3\right)}=\frac{6}{19}\)
a) \(5\frac{8}{17}:x+\frac{-1}{17}:x+3\frac{1}{17}:17\frac{1}{3}=\frac{4}{17}\)
\(\frac{93}{17}:x+\frac{-1}{17}:x+\frac{52}{17}:\frac{52}{3}=\frac{4}{17}\)
\(\left(\frac{93}{17}+\frac{-1}{17}\right):x+\frac{52}{17}.\frac{3}{52}=\frac{4}{17}\)
\(\frac{92}{17}:x+\frac{3}{17}=\frac{4}{17}\)
\(\frac{92}{17}:x=\frac{4}{17}-\frac{3}{17}\)
\(\frac{92}{17}:x=\frac{1}{17}\)
\(x=\frac{92}{17}:\frac{1}{17}\)
\(x=92\)
b) \(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)
\(\frac{1}{3}.\left(1-\frac{1}{4}\right)+\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{7}\right)+\frac{1}{3}.\left(\frac{1}{7}-\frac{1}{10}\right)+...+\frac{1}{3}.\left(\frac{1}{x}-\frac{1}{x+3}\right)=\frac{6}{19}\)
\(\frac{1}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{6}{19}\)
\(\frac{1}{3}.\left(1-\frac{1}{x+3}\right)=\frac{6}{19}\)
\(1-\frac{1}{x+3}=\frac{6}{19}:\frac{1}{3}\)
\(1-\frac{1}{x+3}=\frac{18}{19}\)
\(\frac{1}{x+3}=1-\frac{18}{19}\)
\(\frac{1}{x+3}=\frac{1}{19}\)
\(\Rightarrow x+3=19\)
\(\Rightarrow x=19-3\)
\(\Rightarrow x=16\)
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Tính giá trị của biểu thức A=210×13+210×65/28×104
B=810+410/84+411
C=46×95+69×120/ -84×312 - 611
A = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(A=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}\)
\(A=\frac{2^2.3}{1.4}=3\)
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1)tính hợp lý: \(\dfrac{-5}{13}\times\dfrac{4}{11}+\dfrac{-5}{13}\div\dfrac{11}{7}+\dfrac{18}{13}\)
`[-5]/13xx4/11+[-5]/13:11/7+18/13`
`=[-5]/13xx4/11+[-5]/13xx7/11+18/13`
`=[-5]/13xx(4/11+7/11)+18/13`
`=[-5]/13xx11/11+18/13`
`=[-5]/13+18/13=13/13=1`
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2/7 \(\times\) x = 2/3 x \(\div\) 7/11 = 22
2/7 x X= 2/3
x = 2/3 : 2/7
x = 7/3
x : 7/11 = 22
x = 22 x 7/11
x= 14
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\(\dfrac{2}{7}\) `xx` \(x\)\(=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}:\dfrac{2}{7}\)
\(x=\dfrac{2}{3}\times\dfrac{7}{2}\)
\(x=\dfrac{14}{6}\)
\(x=\dfrac{7}{3}\)
b) \(x:\dfrac{7}{11}=22\)
\(x=22\times\dfrac{7}{11}\)
\(x=\dfrac{154}{11}\)
\(x=14\)
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Xem thêm câu trả lời
a) 49 - 3×(x + 35) = 13
b) 5×(x + 35) = 515
c) 41 - (2x - 5) = 18
d) 75 : (x - 18) = 5²
e) (27x + 6) : 3 - 11 = 9
f) (15 - 6x)× 3^5 = 3^6
j) 5×(x - 35) = 0
k) 30 - [ 4×(x-2) + 15 ] = 3
Giúp em với ạ
Câu 1: Tìm x biết
1,\(5^2\times7^3\times11^2\times x-5^2\times7^2\times11^4=0\)
2,\(5^2\times7^3\times11^2\times x+5^3\times7^2\times11=0\)
vì số nào nhân vs o đều bàng 0 nên x trong cả hai bài trên đều bằng 0
1, x=0
2, x=0
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Tính
a, 4timesleft(-dfrac{1}{2}right)^3-2timesleft(-dfrac{1}{2}right)^2+3timesleft(-dfrac{1}{2}right)+1
b, dfrac{4^6times9^5+6^9times120}{-8^4times3^{12}+6^{11}}
c, dfrac{155-dfrac{10}{7}-dfrac{5}{11}+dfrac{5}{23}}{403-dfrac{26}{7}-dfrac{13}{11}+dfrac{12}{23}}+dfrac{dfrac{3}{5}+dfrac{3}{13}-0,9}{dfrac{7}{91}+0,2-dfrac{3}{10}}
d,dfrac{30times4^7times3^{29}-5times14^5times2^{12}}{54times6^{14}times9^7-12times8^5times7^5}
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Tính
a, 4\(\times\left(-\dfrac{1}{2}\right)^3-2\times\left(-\dfrac{1}{2}\right)^2+3\times\left(-\dfrac{1}{2}\right)+1\)
b, \(\dfrac{4^6\times9^5+6^9\times120}{-8^4\times3^{12}+6^{11}}\)
c, \(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{12}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0,9}{\dfrac{7}{91}+0,2-\dfrac{3}{10}}\)
d,\(\dfrac{30\times4^7\times3^{29}-5\times14^5\times2^{12}}{54\times6^{14}\times9^7-12\times8^5\times7^5}\)
a, \(4\times\left(-\dfrac{1}{2}\right)^3-2\times\left(-\dfrac{1}{2}\right)^2+3\times\left(-\dfrac{1}{2}\right)+1\)
\(=\left(-\dfrac{1}{2}\right)\left[\left(4\times-\dfrac{1}{2}\right)-\left(2\times-\dfrac{1}{2}\right)+3\right]+1\)
\(=\left(-\dfrac{1}{2}\right)\left(-2+1+3\right)+1\)
\(=\left(-\dfrac{1}{2}\right)2+1\)
\(=-1+1\)
\(=0\)
@Trịnh Thị Thảo Nhi
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a, 4×(−12)3−2×(−12)2+3×(−12)+14×(−12)3−2×(−12)2+3×(−12)+1
=(−12)[(4×−12)−(2×−12)+3]+1=(−12)[(4×−12)−(2×−12)+3]+1
=(−12)(−2+1+3)+1=(−12)(−2+1+3)+1
=(−12)2+1=(−12)2+1
=−1+1=−1+1
=0=0
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