tính hợp lí 1+2+3+4+5+(-1)+(-2)+(-3)+(-4)
Tính hợp lí.
( 3 - 1/4 + 2/3 ) - ( 5 -1/3 - 6/5 ) - ( 6 - 7/4 + 3/2 )
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{6}{5}-\frac{3}{2}\right)\)
\(=\left(-8\right)+2+1+\frac{-3}{10}\)
\(=\left(-5\right)+\frac{-3}{10}=\frac{-53}{10}=-5,3\)
(3-1/4+2/3)-(5-1/3-6/5)-(6-7/4+3/2)
=3-1/4+2/3-5-1/3-6/5-6-7/4+3/2
=(3-5-6)+(-1/4-7/4)+(2/3-1/3)+(6/5/3/2
=(-8)+2+1+(-3/10)
=(-5)+(-3/10)=-53/10=-5,3
Tính hợp lí:
3/5×(5/2 - 10/3) - 5/8 : (1/4-2/3)
\(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{5}{2}\) - \(\dfrac{10}{3}\)) - \(\dfrac{5}{8}\): ( \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\))
\(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{2}\) - \(\dfrac{3}{5}\) \(\times\) \(\dfrac{10}{3}\) - \(\dfrac{5}{8}\): (-\(\dfrac{5}{12}\))
= \(\dfrac{3}{2}\) - 2 + \(\dfrac{3}{2}\)
= (\(\dfrac{3}{2}\) + \(\dfrac{3}{2}\)) - 2
= 3 - 2
= 1
Đúng 1
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:(( Giúp Tính hợp lí: 12.(-2/3)+4/3
4/5.(7/2+1/4)^2
\(12.\left(-\frac{2}{3}\right)+\frac{4}{3}\)
\(=-8+\frac{4}{3}\)
\(=\frac{-20}{3}\)
\(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{15}{4}\right)^2\)
\(=\frac{4}{5}.\frac{225}{16}\)
\(=\frac{45}{4}\)
\(12.\left(-\frac{2}{3}\right)+\frac{4}{3}\)
\(=-8+\frac{4}{3}=-\frac{20}{3}\)( bấm máy tính ... số cx ko to lắm nên cx hợp lí :v)
\(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{14}{4}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{15}{4}\right)^2\)
\(=\frac{4}{5}.\frac{225}{16}\)
rút gọn ta đc \(=\frac{45}{4}\)
Tính hợp lí
4\(\dfrac{1}{6}\)- 2\(\dfrac{1}{3}\)+ 3\(\dfrac{7}{12}\) - 5\(\dfrac{3}{4}\)
\(=4+\dfrac{1}{6}-2-\dfrac{1}{3}+3+\dfrac{7}{12}-5-\dfrac{3}{4}\)
\(=\dfrac{1}{6}-\dfrac{1}{3}+\dfrac{7}{12}-\dfrac{3}{4}=\dfrac{2}{12}-\dfrac{4}{12}+\dfrac{7}{12}-\dfrac{9}{12}=0\)
\(=4+\dfrac{1}{6}-2-\dfrac{1}{3}+3+\dfrac{7}{12}-5-\dfrac{3}{4}\)
\(=\left(4-2+3-5\right)+\left(\dfrac{1}{6}-\dfrac{1}{3}+\dfrac{7}{12}-\dfrac{3}{4}\right)\)
\(=0+\dfrac{2-4+7-9}{12}\)
\(=\dfrac{-4}{12}=\dfrac{-1}{3}\)
Tính hợp lí: 1+1+2+3+4+5+...+34
=1+(34+1)x34:2
=1+ 35 x 17
=1+595
=596
Đặt \(A=1+2+3+4+5+...+34\)
Số số hạng của dãy:
\(\left(34-1\right):1+1=34\)
Tổng của A:
\(\left(1+34\right)\times34:2=595\)
Do đó \(1+1+2+3+4+5+...+34=1+595=596\)
Đặt
Số số hạng của dãy:
Tổng của A:
Do đó
=1+(34+1)x34:2
=1+ 35 x 17
=1+595
=59cái này là của lớp 5 nek bạn
Nhớ tick cho mình nha , chúc bạn học tốt
tính bằng cách hợp lí nhất 1 4/7 x 3 4/11 x 3 11/15 x 5 5/8 =
b) 3/4 x 1 1/2 + 3/4 x 1/2 =
2 ý trên là hỗn số
\(a,1\dfrac{4}{7}.3\dfrac{4}{11}.3\dfrac{11}{15}.5\dfrac{5}{8}\)
\(=\dfrac{11}{7}.\dfrac{27}{11}.\dfrac{56}{15}.\dfrac{45}{8}\)
\(=\dfrac{11.27.56.45}{7.11.15.8}\)
\(=\dfrac{1.3.7.3}{1.1.1.1}\)
\(=63\)
\(b,\dfrac{3}{4}.1\dfrac{1}{2}+\dfrac{3}{4}.\dfrac{1}{2}\)
\(=\dfrac{3}{4}.\left(1\dfrac{1}{2}+\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}.2\)
\(=\dfrac{3}{2}\)
tính hợp lí : 1/2+2/5+1/3+5/7+1/6+(-4)/35+1/41
\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{-4}{35}+\dfrac{5}{7}\right)+\dfrac{1}{41}=1+1+\dfrac{1}{41}=\dfrac{83}{41}\)
tính bằng cách hợp lí: B=1*2*3+2*3*4+3*4*5+...+49*50*51
\(B=1.2.3+2.3.4+3.4.5+.......+49.50.51\)
\(\Rightarrow4B=1.2.3.4+2.3.4.4+3.4.5.4+.......+49.50.51.4\)
\(=1.2.3.4+2.3.4\left(5-1\right)+3.4.5\left(6-2\right)+.........+49.50.51.\left(52-48\right)\)
\(=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+.........+49.50.51.52-48.49.50.51\)
\(=49.50.51.52\)
\(\Rightarrow B=\frac{49.50.51.52}{4}=1624350\)
1.tính hợp lí
a) -4/15 *-3/8*15/-4*8
-2/3*4/19+5/3*4/19
-1/2*5/3+1/2*8/3
a) \(-\frac{4}{15}\cdot\left(-\frac{3}{8}\right)\cdot\left(\frac{15}{-4}\right)\cdot8\)
\(=\left(-\frac{4}{15}\cdot\left(\frac{15}{-4}\right)\right)\cdot\left(-\frac{3}{8}\cdot8\right)\)
\(=1\cdot\left(-3\right)=-3\)
b) \(-\frac{2}{3}\cdot\frac{4}{19}+\frac{5}{3}\cdot\frac{4}{19}\)
\(=\frac{4}{19}\cdot\left(\frac{5}{3}-\frac{2}{3}\right)\)
\(=\frac{4}{19}\cdot1=\frac{4}{19}\)
c) \(-\frac{1}{2}\cdot\frac{5 }{3}+\frac{1}{2}\cdot\frac{8}{3}\)
\(=\frac{1}{2}\left(\frac{8}{3}-\frac{5}{3}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)