a ) \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{\left(-11\right)}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{19}{70}\right|\)

=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\frac{19}{70}=\frac{3}{35}\)

=> \(\frac{2}{5}+x+\frac{3}{2}=\frac{3}{7}-\frac{3}{35}=\frac{12}{35}\)

=> \(\frac{2}{5}+x=\frac{12}{35}-\frac{3}{2}=-\frac{81}{70}\)

=> \(x=-\frac{81}{70}-\frac{2}{5}=-\frac{109}{70}\)

b) \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)

=> \(\frac{3}{4}x-6=\frac{5}{2}\)

=> \(\frac{3}{4}x=\frac{17}{2}\)

=> \(x=\frac{17}{2}:\frac{3}{4}=\frac{34}{3}\)

Câu c,d tự làm nhé

a. \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{-11}{70}\right|\)

\(\Rightarrow\frac{3}{7}-\left(\frac{19}{10}+x\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)

\(\Rightarrow\frac{3}{7}-\frac{19}{10}-x=\frac{5}{14}-\left|\frac{19}{70}\right|=\frac{5}{14}-\frac{19}{70}\)

\(\Rightarrow-\frac{103}{70}-x=\frac{3}{35}\)

\(\Rightarrow x=-\frac{103}{70}-\frac{3}{35}\)

\(\Rightarrow x=-\frac{109}{70}\)

b. \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)

\(\Rightarrow\frac{3}{4}\left(x-8\right)=\frac{5}{7}.\frac{7}{2}=\frac{5}{2}\)

\(\Rightarrow x-8=\frac{10}{3}\)

\(\Rightarrow x=\frac{34}{3}\)

c.  \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)

\(\Rightarrow\frac{3}{2}-1+4x=\frac{2}{3}-7x\)

\(\Rightarrow\frac{1}{2}=\frac{2}{3}-7x-4x=\frac{2}{3}-11x\)

\(\Rightarrow11x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\)

\(\Rightarrow x=\frac{1}{66}\)

d. \(4\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)

\(\Rightarrow2-4x-5x+\frac{3}{2}=\frac{7}{4}\)

\(\Rightarrow2-9x=\frac{1}{4}\)

\(\Rightarrow9x=\frac{7}{4}\)

\(\Rightarrow x=\frac{7}{36}\)

a) 8 + 2x = 20

2x = 20 - 8

2x = 12

x = 12 : 2

x = 6

Vậy x = 6

b) 70 - 5(x - 3) = 45

5(x-3) = 70 - 45

5(x-3) = 25

x - 3 = 25 : 5

x - 3 = 5

x = 5 + 3

x = 8

Vậy x = 8

c) (3x - 2^4). 7^3 = 2. 7^4

(3x - 16) . 147 = 2 . 1029

(3x - 16) . 147 = 2058

3x - 16 = 2058 : 147

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3 

x = 10 

Vậy x = 10

a/ 8+2.x=20

    2x=20-8

    2x=12

   x=12:2=4

b/70-5.(x-3)=45

       5.(x-3)=70-45=25

          x-3=25:5=5

          x=5+3=8

c/(3.x-2⁴).7³=2.7⁴

  (3.x-2⁴).7³=4802

  3x-2⁴ =4802:7³=14

  3x=14+2⁴=30

  x=30:3=10

tk nhen

câu 1 là 6 nhé, mk nahaafm

gõ latex đi bn!

a. 2^x + 70 = 74

<=> 2^x = 4

<=> x = 2

b. 120 - \(\dfrac{4x}{2}\) = 80

<=> 120 - 2x = 80

<=> 120 - 80 = 2x

<=> 2x = 40

<=> x = 20

c. (3x + 5)² = 400

<=> \(|3x+5|=\sqrt{400}\)

<=> \(|3x+5|=20\)

<=> \(\left[{}\begin{matrix}3x+5=20\\3x+5=-20\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{-25}{3}\end{matrix}\right.\) 

a)=-1/35=2/70

=>x=2

vậy x= 2

b)ta chia thành 2 vế

vế 1):5/3+-14/3=-11/3=-55/15

vế 2):8/5+18/10=17/5=51/15

từ 2 vế ta có :-55/15<x<51/15

=>x\(\in\){\(\frac{-54}{15}\),.............,\(\frac{50}{15}\)}

vậy x\(\in\){\(\frac{-54}{15}\),.......,\(\frac{50}{15}\)}

      \(\frac{2}{5}+\left(\frac{-3}{7}\right)=\frac{x}{70}\)                     

=>\(\frac{-1}{35}\)                \(=\frac{x}{70}\)

=>\(\frac{-2}{70}\)                \(=\frac{x}{70}\)

VẬY x = -2

b/      \(\frac{5}{3}+\left(\frac{-14}{3}\right)< x< \frac{8}{5}+\frac{18}{10}\)

      =>                      \(-3< x< \frac{17}{5}\)

    =>                      \(-3< x< 3.4\)

    =>        \(x\left\{-2;-1;0;1;2;3\right\}\)

VẬY ............

a, x=-2

b, -3<x<3,4 ,vậy các giá trị nguyên của x là -2;-1;0;1;2;3

a )

     2/5 + -3/7   =   x/70

14/35 + -15/35 = x/70

-1/35                = x/70

=> x = 70x ( -1 ) / 35 = 2

Vậy x = 2

tk mk nha 

cảm ơn mọi người nhiều lắm ạ ! hihi

`@` `\text {Ans}`

`\downarrow`

`a,`

`(x-1954) \times 5=50`

`x-1954 = 50 \div 5`

`x-1954 = 10`

`x=10 + 1954`

`x= 1964`

`B.`

`48 - 40 \times x=8`

`40 \times x=48-8`

`40 \times x = 40`

` x=40 \div 40`

`x=1`

`C.`

`2+70 \div x = 3`

`70 \div x = 3-2`

`70 \div x = 1`

`x=70 \div 1`

`x=70`

`D. [3 \times (x+2) \div 7]  \times  4=120`

`3 \times (x+2) \div 7 = 120 \div 4`

`3 \times (x+2) \div 7 =30`

`3 \times (x+2) = 30 \times 7`

`3 \times (x+2)=210`

`x+2=210 \div 3`

`x+2=70`

`x=70-2`

`x=68`

`E.`

`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.

\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)

a)\(8+2x=20\)

   \(2x=14\)

     \(x=\frac{14}{2}=7\)

               vậy x=7

b)\(70-5\left(x+3\right)=45\)

    \(5\left(x+3\right)=25\)

     \(x+3=5\)

    \(x=2\)

             Vậy \(x=2\)

c)\(\left(3x-2^4\right).7^3=2.7^4\)

    \(\left(3x-16\right)=\frac{2.7^4}{7^3}\)

    \(3x-16=7.2\)

     \(3x-16=14\)

      \(3x=30\)

       \(x=10\)

              Vậy \(x=10\)

a)13-2(x+1)=7

  2.(x+1)=13-7

  2.(x+1)=6

  x+1=6/2

  x+1=3 

  x=3-1

  x=2

a, 13 - 2 ( x + 1 ) = 7

          2 .( x + 1 ) = 13 - 7
          2 .( x + 1 ) = 6
                x + 1   = 6 : 2
                x + 1    = 3
                x          = 3 - 1
                x           = 4

b)6x+2.4=5².2

6x+2=50

6x=48

x=8

c)420+65.4=(x+175):5+30

(x+175):5+30=680

(x+175):5=650

x+175=3250

x=3075

Tìm x

700:7-3*x=36*25:9-70

100-3*x=100-70

100-3*x=30

3*x=70

x=70/3

Câu đầu ko rõ đề lắm nên làm câu 2 ha:

\(\frac{2222}{333}+\frac{111111}{151515}-\frac{2}{5}\)

\(=\frac{2222}{333}+\left(\frac{11}{15}-\frac{6}{15}\right)\)

\(=\frac{2222}{333}+\frac{1}{3}\)

\(=\frac{2222}{333}+\frac{111}{333}=\frac{2333}{333}\)

câu đầu là tính nhanh nha bạn Đình Sang Bùi