a, 9; 7; 5; 2

b, 1; 6; 4; 8

a) 9, 7, 5 2

b) 1, 4, 6, 8

a. 9-7-5-2

b. 1-4-6-8

a: -10/8<-1

-19/19=-1

-1<-2/10<0

0<5/12<1<17/15

=>17/15>1>5/12>-2/10>-19/19>-10/8

b: -1/3=-4/12; -5/12=-5/12; -3/4=-9/12; -1/4=-3/12; -7/12=-7/12

=>-3/4<-7/12<-5/12<-1/3<-1/4

Theo thứ tự từ lớn đến bé:\(\dfrac{17}{15};1;\dfrac{5}{12};0;\dfrac{2}{-10};-\dfrac{19}{19};-\dfrac{10}{8}\)

Theo thứ tự từ bé đến lớn : \(-\dfrac{3}{4};-\dfrac{7}{12};-\dfrac{5}{12};-\dfrac{1}{3};\dfrac{1}{-4}\)

 ` @Answer`

Ta có :

`3/5=(3xx24)/(5xx24)=72/120`

`7/3=(7xx40)/(3xx40)= 280/120`

`6/8=(6xx15)/(8xx15)=90/120`

`5/3=(5xx40)/(3xx40)=200/120`

`-` Thứ tự từ bé đến lớn là :

`->3/5 ;6/8 ; 5/3; 7/3`

3/5<3/4=6/8

5/3<7/3

=>3/5<6/8<5/3<7/3

\(\dfrac{3}{5},\dfrac{7}{3},\dfrac{6}{8},\dfrac{5}{3}\)

msc:120

\(\dfrac{3}{5}=\dfrac{72}{120}\)

\(\dfrac{7}{3}=\dfrac{280}{120}\)

\(\dfrac{6}{8}=\dfrac{90}{120}\)

\(\dfrac{5}{3}=\dfrac{200}{120}\)

do \(\dfrac{72}{120}< \dfrac{90}{120}< \dfrac{200}{120}< \dfrac{280}{120}\)

=>\(\dfrac{3}{5}>\dfrac{6}{8}>\dfrac{5}{3}>\dfrac{7}{3}\)

=> theo thứ tự từ bé đến lớn :\(\dfrac{3}{5},\dfrac{6}{8},\dfrac{5}{3},\dfrac{7}{3}\)

Ta có : \(\dfrac{4}{5}< 1\) ; \(\dfrac{4}{7}< 1\) \((\) vì có cùng tử số mà mẫu số lớn hơn thì bé hơn \()\)

\(\dfrac{2}{1}=2;\dfrac{6}{2}=3;\dfrac{9}{8}>1;\dfrac{8}{5}>1\)

\(\Rightarrow\) thứ tự từ bé đến lớn:\(\dfrac{4}{7};\dfrac{4}{5};\dfrac{9}{8};\dfrac{8}{5};\dfrac{2}{1};\dfrac{6}{2}\)

\(#Vy\)

SOS

\(\dfrac{6}{2}\) ; \(\dfrac{2}{1}\) ; \(\dfrac{8}{5}\) ; \(\dfrac{9}{8}\);\(\dfrac{4}{5}\);\(\dfrac{4}{7}\)

\(@Vy\)

\(\dfrac{6}{2},\dfrac{2}{1},\dfrac{8}{5},\dfrac{9}{8},\dfrac{4}{5},\dfrac{4}{7}\)

4/9 ; 8/9 ; 5/4 ; 4/3 ; 5/3

\(\dfrac{4}{9};\dfrac{8}{9};\dfrac{5}{4};\dfrac{4}{3};\dfrac{5}{3}\)

4/9 ; 8/9 ; 4/3 ; 5/3

3/10 , 2/5 , 1/2 , ,5/8

5/9,8/9,4/4,5/4