\(\dfrac{5}{6}\) + \(\dfrac{7}{8}\)

=     \(\dfrac{5\times4}{6\times4}\) + \(\dfrac{7\times3}{8\times3}\)

=      \(\dfrac{20}{24}\) + \(\dfrac{21}{24}\)

=         \(\dfrac{41}{24}\)

5/6 + 7/8 = 41/24

2 + 2/3 = 8/3

7/9 - 1/7 = 40/63

1-1/11 =10/11

2x17/81 = 34/81

9/11 : 5/6 = 54/55

3: 12/25 = 25/4

                Tick cho mik nhé.

       Chúc bạn học tốt nha !

2 + \(\dfrac{2}{3}\)

= \(\dfrac{2\times3}{1\times3}\) +  \(\dfrac{2}{3}\)

= \(\dfrac{6}{3}\) + \(\dfrac{2}{3}\)

= \(\dfrac{8}{3}\)

a) Ta có: \(x-12=\left(-9\right)-15\)

\(\Rightarrow x-12=-24\)

\(\Rightarrow x=-12\)

b) \(2-x=17-\left(-5\right)\)

\(\Rightarrow2-x=22\)

\(\Rightarrow x=2-22\)

\(\Rightarrow x=-20\)

c) \(11-\left(15+11\right)=x-\left(25-9\right)\)

\(\Rightarrow-15=x-16\)

\(\Rightarrow x=1\)

d) \(x-\left(17-x\right)=x-7\)

\(\Rightarrow x-17+x=x-7\)

\(\Rightarrow x+x-x=-7+17\)

\(\Rightarrow x=10\)

e) \(9-25=\left(7-x\right)-\left(25+7\right)\)

\(\Rightarrow9-25=7-x-25-7\)

\(\Rightarrow-16=-25-x\)

\(\Rightarrow x=-9\)

g) \(x-13=21-x\)

\(\Rightarrow x+x=21+13\)

\(\Rightarrow2x=34\)

\(\Rightarrow x=17\)

a, x - 12 = ( -9 ) - 15 

x - 12 = -24

x = -24 + 12

x = -12

b, 2 - x = 17 - ( -5 )

2 - x = 22

x = 2 - 22

x = -20

c, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11 - 26 = x - 16

-15 = x - 16

x = -15 + 16 

x = 1

d, x - ( 17 - x ) = x - 7

x - 17 + x = x - 7

x + x - 17 = x - 7

x + x - x = -7 + 17

x = 10

e.9 - 25 = ( 7- x ) - ( 25 + 7 )

-16 = ( 7 - x ) -32

7 - x = -32 + 16 

7 - x = 16

x = 7 - 16

x= -9

g, x - 13 = 21 - x

x + x = 21 + 13

2x = 44

x = 44 : 2

x=22

A= -12

B=-20

C=1

D=17

E=-9

G=17

a: \(\Leftrightarrow x\cdot\dfrac{1}{2}=\dfrac{1}{4}\cdot\dfrac{-7}{2}+\dfrac{5}{3}=\dfrac{19}{24}\)

hay x=19/12

b: \(\Leftrightarrow\left(\dfrac{45}{11}-3x\right)\cdot\dfrac{11}{5}=\dfrac{21}{5}\)

\(\Leftrightarrow-3x+\dfrac{45}{11}=\dfrac{21}{11}\)

=>-3x=-24/11

=>x=8/11

c: \(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\5-\dfrac{1}{2}x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=10\end{matrix}\right.\)

d: \(\Leftrightarrow\left(2x+\dfrac{3}{5}\right)^2=\dfrac{16}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+\dfrac{3}{5}=\dfrac{4}{5}\\2x+\dfrac{3}{5}=-\dfrac{4}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{10}\\x=-\dfrac{7}{10}\end{matrix}\right.\)

a, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11-15-11=x-25+9

-15=x-16

x=1

b, 2 - x = 17 - ( - 5 )

2-x=22

x=-20

c, x - 12 = ( - 9 ) - 15

x-12=-24

x=-12

d, 9 - 25 = ( 7 - x ) - ( 25 + 7 )

(7-x)-32=-16

7-x=16

x=-9

#H

9 - 25 = 7  - x - 25 - 7 

-16 = 7 - x - 32

<=> 7-x-32 = -16

7-x = -16 + 32 = 16

x = 7 - 16 = -9

x=-9 

tk cho bạn ấy đi , đúng rùi đấy

X-1/4.x=6/11.(6/12+9/12+-4/12)

X-1/4.x=6/11.11/12

X-1/4.x=1/2

X.(1-1/4)=1/2

X.(4/4+-1/4)=1/2

X.3/4=1/2

X=1/2:3/4

X=1/2.4/3

X=2/3

Giai thich trong mot bai toan neu co hai dau x ta se ko tinh duoc trong bai toan nay x-25℅.x=6/11.(1/2+3/4+1/3) co hai dau x nen ta phai dua x ra ngoai lam h chung x dung mot minh se la x.1 khi ta bo x ra ngoai thi ben trong con 1-25℅ roi ta tinh ra sau do lam binh thuong

Lời giải:
a.

$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$

b.

$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$

c.

$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$

$x=(-1).\frac{-8}{9}=\frac{8}{9}$