Bài 4: 

a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)

b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)

Bài 4: 

a: =11/21(7/4+5/4)=11/21x3=11/7

b: =6/13(23/14-9/14)=6/13

f(x) có nghiệm là  \(x=-5\)   nên ta có:

\(f\left(-5\right)=-\left(-5\right)^2-2\left(m-1\right).\left(-5\right)+7m+6=0\)

\(\Leftrightarrow\)\(-25+10\left(m-1\right)+7m+6=0\)

\(\Leftrightarrow\)\(17m=29\)

\(\Leftrightarrow\)\(m=\frac{29}{17}\)

Vậy...

1:

a: TH1: x<-3

=>-x-3+10-2x=12

=>-3x+7=12

=>-3x=5

=>x=-5/3(loại)

TH2: -3<=x<5

=>x+3+10-2x=12

=>13-x=12

=>x=1(nhận)

Th3: x>=5

=>x+3+2x-10=12

=>3x=19

=>x=19/3(nhận)

b: =>|2x|+|2x-4|=x+1

TH1: x<0

=>-2x+4-2x=x+1

=>-4x+4-x-1=0

=>-5x=-3

=>x=3/5(loại)

TH2: 0<=x<2

=>2x+4-2x=x+1

=>x=3(loại)

TH3: x>=2

=>2x+2x-4=x+1

=>3x=5

=>x=5/3(loại)

a) -3.(x-5) + 6.(x+2) = 9

-3x + 15 + 6x + 12 = 9

3x + 27 = 9

3x = -18

x = -6

b) 7.(x-9) - 5.(6-x) = -6 + 11.x

7x - 63 - 30 + 5x = - 6 +  11.x

=> 12x - 11x = - 6 + 63 + 30

x = 87

c) 10.(x-7) - 8.(x+5) = 6.(-5) + 24

10x - 70 -8x - 40 = -6

2x - 110 = - 6

2x = 104

x = 52

\(-3\left(x-5\right)+6\left(x+2\right)=9\)

\(\Rightarrow-3x+15+6x+12=9\)

\(\Rightarrow-3x+6x=9-15-12\)

\(\Rightarrow3x=-18\)\(\Rightarrow x=-6\)

\(7\left(x-9\right)-5\left(6-x\right)=-6+11x\)

\(\Rightarrow7x-63-30+5x=-6+11x\)

\(\Rightarrow7x+5x-11x=-6+63+30\)

\(\Rightarrow x=-6+63+30=87\)