chung minh 4:3=2
a)chung minh A= 2^1+2^2+2^3+2^4+...2^2010chia het cho 3
b)chung minh B= 3^1+3^2+3^3+3^4+...3^2010chia het cho 4
c)chung minh C= 5^1+5^2+5^3+5^4+...5^2010chia het cho 6
d)chung minh D= 7^1+7^2+7^3+7^4+...7^2010chia het cho 8
a) A=21+22+23+...+22010
A=(21+22)+(23+24)+.....+(22009+22010)
A=(21x3)+(23x3)+.....+(22009x3)
A=3x(21+23+.......+22009)
Vậy A chia hết cho 3.
NHỮNG CÂU CÒN LẠI BẠN LÀM TƯƠNG TỰ !
chung minh rang 4+4^3+4^5+4^7+...+4^23 chia het cho 68
chung minh rang 1+3+3^2+3^3+...+3^2000 chia het cho 13
giup mink voi thu 6 mink nop roi
4 + 4^3 + 4^5 + 4^7 + ... + 4^23
= ( 4 + 4^3 ) + ( 4^5 + 4^7 ) +.....+ ( 4^22 + 4^23)
=4( 1+16 ) + 4^5( 1+16 ) +....+ 4^22( 1+ 16 )
=4 x 17 + 4^5 x 17+....+ 4^22 x 17 chia hết cho 68
Câu 2:
1+3+3^2+3^3+....+3^2000
=( 1+3 +3^2 ) + ( 3^3 + 3^4 + 3^5 ) +.....+ ( 3^ 1998 + 3^1999 + 3^2000)
=1( 1+ 3 + 9 ) + 3^3 + ( 1+ 3 + 9 ) +......+ 3^1998+( 1+ 3 + 9 )
= 1 x 13+ 3^3 x 13 +......+ 3^1998 x 13 chia hết cho 13
k mk nha lần sau mk k lại
Câu 1 nha : 4+4^3+4^5+4^7+....+4^23 = (4+4^3)+(4^5+4^7)+....+(4^21+4^23)
= 68 + 4^4.(4+4^3)+....+4^20.(4+4^3) = 68 + 4^4.68 + .... + 4^20.68
=68.(1+4^4+....+4^20) chia hết cho 68
Câu 2 nha 1+3+3^2+...+3^2000 = (1+3+3^2)+(3^3+3^4+3^5)+....+(3^1998+3^1999+3^2000)
= 13 + 3^3.(1+3+3^2)+....+3^1998.(1+3+3^2) = 13+3^3.13+....+3^1998.13
=13.(1+3^3+....+3^1998) chia hết cho 13
chung minh A= 2 + 2^2 +2^3 +2^4 +.........+2^60 chia het cho 7
tim so tu nhien n de : n+4 chia het cho n+1
chung minh ( 1+2 +2^2 +2^3+2^4+2^5+2^6+2^7) chia het cho 3
1. A = 2 + 22 + 23 + 24 + ... + 260
A = ( 2 + 22 + 23 ) + ( 24 + 25 + 26 ) + ... + ( 258 + 259 + 260 )
A = 2 ( 1 + 2 + 22 ) + 24 ( 1 + 2 + 22 ) + ... + 258 ( 1 + 2 + 22 )
A = 2 . 7 + 24 . 7 + ... + 258 . 7
A = ( 2 + 24 + ... + 258 ) . 7 => A \(⋮\)7
Vậy ...
2.Ta có : \(n+4⋮n+1\)
Mà : \(n+1⋮n+1\)
\(\Rightarrow\left(n+4\right)-\left(n+1\right)⋮n+1\Rightarrow n+4-n-1⋮n+1\)
\(\Rightarrow3⋮n+1\Rightarrow n+1\in\left\{1;3\right\}\)
\(\Rightarrow n\in\left\{0;2\right\}\)
3. Đặt B = 1 + 2 + 22 + 23 + 24 + 25 + 26 + 27
B = ( 1 + 2 ) + ( 22 + 23 ) + ( 24 + 25 ) + ( 26 + 27 )
B = ( 1 + 2 ) + 22 ( 1 + 2 ) + 24 ( 1 + 2 ) + 26 ( 1 + 2 )
B = 1 . 3 + 22 . 3 + 24 . 3 + 26 . 3
B = ( 1 + 22 + 24 + 26 ) . 3 \(\Rightarrow\) B \(⋮\)3
Vậy ...
chung minh M= 3+ 3^2 + 3^3 + 3^4 +......+ 3^2017 +3^2018 + 3 ^ 2019 chia hết cho 3
chung minh A= (n+3)(n+8)luôn chia hết cho 2 với mọi n
a) Ta có: \(M=3+3^2+3^3+...+3^{2017}+3^{2018}+3^{2019}\)
\(=3.\left(1+3+3^2+3^3+...+3^{2016}+3^{2017}+3^{2018}\right)\)
\(\Rightarrow M⋮3\)
_Học tốt_
chung minh 4:3=2
4 là tứ
3 là tam
4 : 3 = tứ : tam = tám : tư = 8 : 4 =2
chung minh 4:3=2
dễ! 4 là Tứ, 3 là Tam. Suy ra, Tứ chia Tam là Tám chia Tư mà 8 : 4 = 2
k nha
thanks you
a,A=1/1^2+1/2^2+1/3^2+1/4^2+...+1/50^2.chung minh rang a<2
b;2^1+2^2+2^3+...+2^30.chung minh rang B chia het cho21
chung minh rang 1/2+2/3+3/4+ ....+99/100<1
nhanh minh tick
Ta có : 1/2 = 0,5
2/3 = 0,666...
=> 1/2 + 2/3 + ... + 99/100 = 0,5 + 0,666...+3/4 + ... + 99/100
= 1,1,6666... + 3/4 + ... +99/100 > 1
=> 1/2 + 2/3 + ... + 99/100 > 1
\(=\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{99}{100}\le1\)
\(=\frac{2-1}{2}+\frac{3-1}{3}+\frac{4-1}{4}+...+\frac{100-1}{100}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\le1\)
\(\Rightarrow1-\frac{1}{100}\le1\)
1/2 + 2/3 + 3/4 + ... + 99/100 < 1
= 2/2 - 1/2 + 3/3 - 1/3 + 4/4 - 1/4 + ... + 100/100 - 1/100
= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100
= 1 - 1/100 < 1 (đpcm)
Hãy chung minh 4:3=2
4= tứ
3= tam
tứ chia tam=tám chia tứ
=> tám chia tư =2
bốn chia ba = tám chia tư =hai
=> 4 : 3 =2
\(4:3\)= 2 \(\Leftrightarrow\)TỨ : TAm
\(\Leftrightarrow\)TÁM : TƯ
\(\Leftrightarrow\)8 : 4=2 ( ĐIỀU Này rõ ràng )