\(\dfrac{-2}{1.3}-\dfrac{2}{3.5}-\dfrac{2}{5.7}-...-\dfrac{2}{19.21}-\dfrac{2}{21.23}-\dfrac{2}{23.25}-\dfrac{2}{25.27}-\dfrac{1}{27}\)\(=\dfrac{-2}{1.3}+\dfrac{-2}{3.5}+\dfrac{-2}{5.7}+...+\dfrac{-2}{19.21}+\dfrac{-2}{21.23}+\dfrac{-2}{23.25}+-\dfrac{2}{25.27}-\dfrac{1}{27}\)Đặt:

\(A=\dfrac{-2}{1.3}+\dfrac{-2}{3.5}+\dfrac{-2}{5.7}+...+\dfrac{-2}{19.21}+\dfrac{-2}{21.23}+\dfrac{-2}{23.25}+\dfrac{-2}{25.27}\)\(A=-1\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{25}-\dfrac{1}{27}\right)\)

\(A=-1\left(1-\dfrac{1}{27}\right)\)

\(A=-1.\dfrac{26}{27}=-\dfrac{26}{27}\)

Thay vào biểu thức ban đầu ta có:

Giá trị là:

\(-\dfrac{26}{27}-\dfrac{1}{27}=-\dfrac{27}{27}=-1\)

cũng dễ mà

mk ghi kết quả thui ha

a) = 250

b) = -27

c) = -3

tick nhé

a) =250        b) =-27          c) =-3

\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)

\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)

\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)

\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)

\(=0,2-\dfrac{2}{3}\)

\(=-\dfrac{7}{15}\)

\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)

\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)

\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)

\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)

\(=\dfrac{13}{26}\)

\(=\dfrac{1}{2}\)

#\(Toru\)

\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)

10) 37.(27+25)-27.(37+25)=37.27+37.25-27.37-27.25

=37.25-27.25=25(37-27)=25.10=250

11)3.(-5+3)+7(2+5)=3.(-2)+7.7=-6+49=43

12)-3.(2-7)-6(8-5)=-3.(-5)-6.3=15-18=-3

a) 37. (27 +25)-27.(37+25)

= 37.52-27.62

= (37-27).(52-62)

= 10.-10

=-100

b) 3.(-5+3)+7.(2-5)

= 3.-2+7.-3

= (3+7).[(-2)-(-3)]

=10.1

=10

c) -3.(2-7)-6.(8-5)

= -3.-5-6.3

= (-3-6).(-5-3)

=(-9).(-8)

=72

tick nha

2/25=.2../25                                                                                                               .27../36=3/4                                         

3/.12..=9/36

15/27=5/..9.. 

..20..28=5/7

36/72=..1../2

\(\dfrac{2}{25}=\dfrac{2}{25}\)
\(\dfrac{27}{36}=\dfrac{3}{4}\)
\(\dfrac{3}{12}=\dfrac{9}{36}\)
\(\dfrac{15}{27}=\dfrac{5}{9}\)
\(\dfrac{20}{28}=\dfrac{5}{7}\)
\(\dfrac{36}{72}=\dfrac{1}{2}\)

TK
2/25=.2../25
27../36=3/4                                        
3/.12..=9/36

15/27=5/..9.. 

..20..28=5/7

36/72=..1../2

a: \(=3\sqrt{3}-2\sqrt{3}+4\sqrt{3}-5\sqrt{3}=2\sqrt{3}\)

câu cuối là 999,7650928....

rồi mà, câu 3 là 100 

khó quá tui chưa học

a) \(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

b) \(27.3^x=243\)

\(3^x=243:27\)

\(3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

c) \(3^x+25=26.2^2+2.3^0\)

\(3^x+25=104+2\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

d) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(7x=10+11\)

\(7x=21\)

\(x=21:7\)

\(x=3\)

e) \(3^x.3=27\)

\(3^x=27:3\)

\(3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

a) \(2^x-15=17\)

\(\Leftrightarrow2^x=17+15\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)

Vậy x = 5

b) \(27.3^x=243\)

\(\Leftrightarrow3^x=243:27\)

\(\Leftrightarrow3^x=9\)

\(\Leftrightarrow3^x=3^2\)

\(\Leftrightarrow x=2\)

Vậy x = 2

c) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow\left(7x-11\right)^3=10^3\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=10+11\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=21:7\)

\(\Leftrightarrow x=3\)

Vậy x = 3

d) \(3^x.3=27\)

\(\Leftrightarrow3^x=27:3\)

\(\Leftrightarrow3^x=9\)

\(\Leftrightarrow3^x=3^2\)

\(\Leftrightarrow x=2\)

Vậy x = 2

_Chúc bạn học tốt_

a) (x - 1/2)² = 4

<=> (x - 1/2)² = 2²

<=> x - 1/2 = -2; 2

<=> x - 1/2 = 2 hoặc x - 1/2 = -2

       x = 2 + 1/2         x = -2 + 1/2

       x = 5/2               x = -3/2

=> x = 5/2 hoặc x = -3/2

b) 10/1/2 - (x + 1/3)² = 1/1/2

<=> -(x + 1/3)² = 1/1/2 - 10/1/2

<=> -(x + 1/3)² = 1/2 - 5

<=> -(x + 1/3)² = -5.2 + 1/2

<=> -(x + 1/3)² = -9/2

<=> (x + 1/3)² = 9/2

<=> x + 1/3 = \(\sqrt{\frac{9}{2}}\)  hoặc x + 1/3 = \(-\sqrt{\frac{9}{2}}\)

       x = \(\frac{3\sqrt{2}}{2}\) - 1/3         x = \(-\frac{3\sqrt{2}}{2}\) -1/3

=> x = \(\frac{3\sqrt{2}}{2}\) - 1/3 hoặc x = \(-\frac{3\sqrt{2}}{2}\) -1/3

c) (x - 1/5)² + 17/25 = 26/25

<=> (x - 1/5)² = 26/25 - 17/25

<=> (x - 1/5)² = (3/5)²

<=> x - 1/5 = -3/5; 3/5

<=> x - 1/5 = 3/5 hoặc x - 1/5 = -3/5

       x = 3/5 + 1/5         x = -3/5 + 1/5

       x = 4/5                  x = -2/5

=> x = 4/5 hoặc x = -2/5