=232×(68+31+1)

=232×100

=23200

Hok tốt!

Tết vui vẻ nha!

232 x 68 + 232 x 31 + 232

= 232 x ( 68 + 31 + 1 ) 

= 232 x 100

= 23200

= 232*68*21+232*1

= 232*(68+21+1)

= 232*100

=23200

Chuk bn năm mới hok tốt :)

x + 19 =1476

x = 1476 - 19 

x = 1457

x - 1223 =432 

x = 432 + 1223

x = 1655

k mình nha

\(x+19=123x12\)

\(x+19=1476\)

\(x=1476-19=1457\)

X=1476-19=1457                 X= 1655

a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)

= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)

= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)

b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)

= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)

\(\frac{1-\frac{6}{23}+\frac{6}{31}-\frac{6}{154}}{\frac{5}{2}-\frac{15}{23}+\frac{15}{31}-\frac{15}{154}}\)

\(=\frac{\frac{6}{6}-\frac{6}{23}+\frac{6}{31}-\frac{6}{154}}{\frac{15}{6}-\frac{15}{23}+\frac{15}{31}-\frac{15}{154}}\)

\(=\frac{6\left(\frac{1}{6}-\frac{1}{23}+\frac{1}{31}-\frac{1}{154}\right)}{15\left(\frac{1}{6}-\frac{1}{23}+\frac{1}{31}-\frac{1}{154}\right)}\)

\(=\frac{6}{15}=\frac{2}{5}\)

mk sửa đề tí nhé